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Omniscience

  • 2 years ago

Jane has three red shirts and two yellow shirts. On each of the three days, Monday, Tuesday, and Wednesday, she selects one shirt at random to wear. Jane wears each shirt that she selects only once. (a) What is the probability that Jane wears a shirt of the same colour on all three days?

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  1. Omniscience
    • 2 years ago
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    Do i use the probability tree diagram? if yes, how do i draw it? i havent done in a very long time..

  2. Omniscience
    • 2 years ago
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    done these*

  3. sami-21
    • 2 years ago
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    Jane has three shirts and two yellow shirts. ???? three red ?

  4. Omniscience
    • 2 years ago
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    woops typo "three red shirts and two yellow shirts" sorry!

  5. Omniscience
    • 2 years ago
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    @lgbasallote: very easy one for you :P

  6. lgbasallote
    • 2 years ago
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    sorry cant understand problem. i am bad english

  7. Omniscience
    • 2 years ago
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    lol, illiterate :P i need help tho -_- i dont know how to draw the tree diagram

  8. lgbasallote
    • 2 years ago
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    |dw:1344425523056:dw|

  9. Omniscience
    • 2 years ago
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    that is not write tho sami

  10. Omniscience
    • 2 years ago
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    right* lol

  11. sami-21
    • 2 years ago
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    i think both probabilities should be multiplied . try that :P

  12. Omniscience
    • 2 years ago
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    the answer is 3/4 * 2/4 * 1/3 but the problem is that i dont know how to draw the probability tree diagram to see it

  13. hoblos
    • 2 years ago
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    the two yellow shirts are not enough for three days.. so we are finding the probability that she wear a red shirt each day on monday the probability that she wear a red shirt is 3/5 (since we have 3 red shirts out of a total of 5 shirts) on tuesday we have only 4 shirts left.. 2 of them are red so the probability that she wears a red shirt on tuesday is 2/4 on wednesday 3 shirts are left.. only one of the is red so the probability thet she wears a red shirt on wednesday is 1/3 now multiply them the answer is (3/5)*(2/4)*(1/3)

  14. Omniscience
    • 2 years ago
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    i got it thanks! but it is possible to draw a probability tree diagram for it?

  15. Omniscience
    • 2 years ago
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    is it*

  16. hoblos
    • 2 years ago
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    well.. may be :P im not that good in drawing tree diagrams !

  17. Omniscience
    • 2 years ago
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    ok ty anyway

  18. hoblos
    • 2 years ago
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    glad to help :)

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