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## mathslover Please see attachment .. one year ago one year ago

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1. mathslover

Help!!!

2. mathslover

well i know that: a:b :: c:d that is a*d = b*c

3. mukushla

multiply 2 sides of equation by $$a$$ then simplify see what happens

4. abdul_shabeer

b+c+{(a-c)(a-b)/a} first add these two

5. abdul_shabeer

What do you get?

6. mathslover

Ok wait

7. mathslover

well you meant like this?: $\large{a(a+d)=a(b+c+\frac{(a-b)(a-c)}{a})}$ $\large{a^2+ad=ab+ac+(a-b)(a-c)}$

8. mukushla

mukushla is not typing a reply… whats the problem with site?

9. abdul_shabeer

In proof you should start with any one side and reach the other side

10. mathslover

$\large{a^2+ad=ab+ac+a^2-ac-ab+bc}$ $\large{a^2+ad=a^2+bc}$ @mukushla I also dont know .. and it is showing you offline

11. mukushla

well ad=bc and we are done

12. mathslover

off topic attachment sorry

13. mathslover

Oh yes right @mukushla thanks a lot

14. mukushla

yw....:)

15. abdul_shabeer

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16. abdul_shabeer

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17. abdul_shabeer

In proof you cannot multiply both sides by a