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well i know that: a:b :: c:d that is a*d = b*c
multiply 2 sides of equation by \(a\) then simplify see what happens

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b+c+{(a-c)(a-b)/a} first add these two
What do you get?
Ok wait
well you meant like this?: \[\large{a(a+d)=a(b+c+\frac{(a-b)(a-c)}{a})}\] \[\large{a^2+ad=ab+ac+(a-b)(a-c)}\]
mukushla is not typing a reply… whats the problem with site?
In proof you should start with any one side and reach the other side
\[\large{a^2+ad=ab+ac+a^2-ac-ab+bc}\] \[\large{a^2+ad=a^2+bc}\] @mukushla I also dont know .. and it is showing you offline
well ad=bc and we are done
off topic attachment sorry
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Oh yes right @mukushla thanks a lot
yw....:)
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In proof you cannot multiply both sides by a

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