alright then, lets start with the first problem
we have the points (2 ,2) & (6,3)
so we substitute those into the the point slope form given
y2-y1=m(x2-x1)
and find m
3-2 = m(6-2)
1 = m *4
m= 1/4
once we have m
we substitute this back into the equation with one of the two points
so y-2= (1/4) (x-2),
at this point, you multiply, distribute and do whatever you need to do to this system in order to make it look like
Ax+Bx=C
or if you need it in point intercept form
once you have m, substitute a point and m into the point intercept equation and solve for b
y=mx+b
remember that x intercept is always (x,0)
and y- intecept is always (0,y)