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pratu043
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ABC and DBC are two triangles on the same base BC such that A and D lie on the opposite sides of BC, AB = AC and DB = DC. Show that AD is the perpendicular bisector of BC.
 one year ago
 one year ago
pratu043 Group Title
ABC and DBC are two triangles on the same base BC such that A and D lie on the opposite sides of BC, AB = AC and DB = DC. Show that AD is the perpendicular bisector of BC.
 one year ago
 one year ago

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pratu043 Group TitleBest ResponseYou've already chosen the best response.0
dw:1344485886935:dw
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
dw:1344486523841:dw
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
1...show that triangle ABD=triangle ACD......it gives BE=EC 1...show that triangle ABE=triangle AEC......it gives <AEB=<AEC=90
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
I have shown that triangle ABD = ACD, but I don't know how to do the other one.
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
triangle ABE=triangle AEC because 1...AC=AB 2...BE=EC 3...AE=AE
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
But we have to prove that BE = EC right?
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
Perpendicular bisector.
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
u've shown that triangle ABD=triangle ACD am i right?
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
sorry if I take a little long to reply.
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
well it gives BE = EC
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
I mean, its not a side of ABD or ACD.
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
u r right ... thats not a complete proof... lets think again...
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
we need to show that triangle ABE=triangle AEC...........
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
try to find 2 angles equal...and one side equal for that 2 triangle
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
dw:1344488387156:dw
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
so that you don't need to scroll up too much.
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
lol.........:)
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
we proved that triangle ABD=triangle ACD so that... <BAE=<CAE and what is the third condition?
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
AE is common so triangle AEB = AEC.
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
we are done
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
But how does that prove that AD is the perpendicular bisector?
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
We should prove that AD bisects BC and angle AEB = 90 degrees.
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
it provides BE=EC and <AEB=<AEC but we know that <AEB+<AEC=180
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
Thanks a lot mukushla!!!
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
yw......:)
 one year ago
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