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pratu043
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ABC and DBC are two triangles on the same base BC such that A and D lie on the opposite sides of BC, AB = AC and DB = DC. Show that AD is the perpendicular bisector of BC.
 2 years ago
 2 years ago
pratu043 Group Title
ABC and DBC are two triangles on the same base BC such that A and D lie on the opposite sides of BC, AB = AC and DB = DC. Show that AD is the perpendicular bisector of BC.
 2 years ago
 2 years ago

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pratu043 Group TitleBest ResponseYou've already chosen the best response.0
dw:1344485886935:dw
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
dw:1344486523841:dw
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
1...show that triangle ABD=triangle ACD......it gives BE=EC 1...show that triangle ABE=triangle AEC......it gives <AEB=<AEC=90
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
I have shown that triangle ABD = ACD, but I don't know how to do the other one.
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
triangle ABE=triangle AEC because 1...AC=AB 2...BE=EC 3...AE=AE
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
But we have to prove that BE = EC right?
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
Perpendicular bisector.
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
u've shown that triangle ABD=triangle ACD am i right?
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
sorry if I take a little long to reply.
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
well it gives BE = EC
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
I mean, its not a side of ABD or ACD.
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
u r right ... thats not a complete proof... lets think again...
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
we need to show that triangle ABE=triangle AEC...........
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
try to find 2 angles equal...and one side equal for that 2 triangle
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
dw:1344488387156:dw
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
so that you don't need to scroll up too much.
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
lol.........:)
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
we proved that triangle ABD=triangle ACD so that... <BAE=<CAE and what is the third condition?
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
AE is common so triangle AEB = AEC.
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
we are done
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
But how does that prove that AD is the perpendicular bisector?
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
We should prove that AD bisects BC and angle AEB = 90 degrees.
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
it provides BE=EC and <AEB=<AEC but we know that <AEB+<AEC=180
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
Thanks a lot mukushla!!!
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.2
yw......:)
 2 years ago
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