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ok

1...show that triangle ABD=triangle ACD......it gives BE=EC
1...show that triangle ABE=triangle AEC......it gives

I have shown that triangle ABD = ACD, but I don't know how to do the other one.

triangle ABE=triangle AEC because
1...AC=AB
2...BE=EC
3...AE=AE

But we have to prove that BE = EC right?

Perpendicular bisector.

u've shown that triangle ABD=triangle ACD
am i right?

yes.

sorry if I take a little long to reply.

np....:)

well it gives BE = EC

But how?

I mean, its not a side of ABD or ACD.

u r right ... thats not a complete proof... lets think again...

we need to show that triangle ABE=triangle AEC...........

try to find 2 angles equal...and one side equal for that 2 triangle

AB = AC

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so that you don't need to scroll up too much.

lol.........:)

we proved that triangle ABD=triangle ACD so that...

AE is common so triangle AEB = AEC.

we are done

But how does that prove that AD is the perpendicular bisector?

We should prove that AD bisects BC and angle AEB = 90 degrees.