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anonymous
 3 years ago
ABC and DBC are two triangles on the same base BC such that A and D lie on the opposite sides of BC, AB = AC and DB = DC. Show that AD is the perpendicular bisector of BC.
anonymous
 3 years ago
ABC and DBC are two triangles on the same base BC such that A and D lie on the opposite sides of BC, AB = AC and DB = DC. Show that AD is the perpendicular bisector of BC.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1344485886935:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1344486523841:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.01...show that triangle ABD=triangle ACD......it gives BE=EC 1...show that triangle ABE=triangle AEC......it gives <AEB=<AEC=90

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I have shown that triangle ABD = ACD, but I don't know how to do the other one.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0triangle ABE=triangle AEC because 1...AC=AB 2...BE=EC 3...AE=AE

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But we have to prove that BE = EC right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Perpendicular bisector.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0u've shown that triangle ABD=triangle ACD am i right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry if I take a little long to reply.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well it gives BE = EC

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I mean, its not a side of ABD or ACD.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0u r right ... thats not a complete proof... lets think again...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we need to show that triangle ABE=triangle AEC...........

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0try to find 2 angles equal...and one side equal for that 2 triangle

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1344488387156:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so that you don't need to scroll up too much.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we proved that triangle ABD=triangle ACD so that... <BAE=<CAE and what is the third condition?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0AE is common so triangle AEB = AEC.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But how does that prove that AD is the perpendicular bisector?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0We should prove that AD bisects BC and angle AEB = 90 degrees.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it provides BE=EC and <AEB=<AEC but we know that <AEB+<AEC=180

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks a lot mukushla!!!
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