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pratu043 Group Title

ABC and DBC are two triangles on the same base BC such that A and D lie on the opposite sides of BC, AB = AC and DB = DC. Show that AD is the perpendicular bisector of BC.

  • one year ago
  • one year ago

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  1. pratu043 Group Title
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    |dw:1344485886935:dw|

    • one year ago
  2. mukushla Group Title
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    |dw:1344486523841:dw|

    • one year ago
  3. pratu043 Group Title
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    ok

    • one year ago
  4. mukushla Group Title
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    1...show that triangle ABD=triangle ACD......it gives BE=EC 1...show that triangle ABE=triangle AEC......it gives <AEB=<AEC=90

    • one year ago
  5. pratu043 Group Title
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    I have shown that triangle ABD = ACD, but I don't know how to do the other one.

    • one year ago
  6. mukushla Group Title
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    triangle ABE=triangle AEC because 1...AC=AB 2...BE=EC 3...AE=AE

    • one year ago
  7. pratu043 Group Title
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    But we have to prove that BE = EC right?

    • one year ago
  8. pratu043 Group Title
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    Perpendicular bisector.

    • one year ago
  9. mukushla Group Title
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    u've shown that triangle ABD=triangle ACD am i right?

    • one year ago
  10. pratu043 Group Title
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    yes.

    • one year ago
  11. pratu043 Group Title
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    sorry if I take a little long to reply.

    • one year ago
  12. mukushla Group Title
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    np....:)

    • one year ago
  13. mukushla Group Title
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    well it gives BE = EC

    • one year ago
  14. pratu043 Group Title
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    But how?

    • one year ago
  15. pratu043 Group Title
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    I mean, its not a side of ABD or ACD.

    • one year ago
  16. mukushla Group Title
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    u r right ... thats not a complete proof... lets think again...

    • one year ago
  17. mukushla Group Title
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    we need to show that triangle ABE=triangle AEC...........

    • one year ago
  18. mukushla Group Title
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    try to find 2 angles equal...and one side equal for that 2 triangle

    • one year ago
  19. pratu043 Group Title
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    AB = AC

    • one year ago
  20. pratu043 Group Title
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    |dw:1344488387156:dw|

    • one year ago
  21. pratu043 Group Title
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    so that you don't need to scroll up too much.

    • one year ago
  22. mukushla Group Title
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    lol.........:)

    • one year ago
  23. mukushla Group Title
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    we proved that triangle ABD=triangle ACD so that... <BAE=<CAE and what is the third condition?

    • one year ago
  24. pratu043 Group Title
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    AE is common so triangle AEB = AEC.

    • one year ago
  25. mukushla Group Title
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    we are done

    • one year ago
  26. pratu043 Group Title
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    But how does that prove that AD is the perpendicular bisector?

    • one year ago
  27. pratu043 Group Title
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    We should prove that AD bisects BC and angle AEB = 90 degrees.

    • one year ago
  28. mukushla Group Title
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    it provides BE=EC and <AEB=<AEC but we know that <AEB+<AEC=180

    • one year ago
  29. pratu043 Group Title
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    Thanks a lot mukushla!!!

    • one year ago
  30. mukushla Group Title
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    yw......:)

    • one year ago
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