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pratu043
 3 years ago
ABC and DBC are two triangles on the same base BC such that A and D lie on the opposite sides of BC, AB = AC and DB = DC. Show that AD is the perpendicular bisector of BC.
pratu043
 3 years ago
ABC and DBC are two triangles on the same base BC such that A and D lie on the opposite sides of BC, AB = AC and DB = DC. Show that AD is the perpendicular bisector of BC.

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mukushla
 3 years ago
Best ResponseYou've already chosen the best response.21...show that triangle ABD=triangle ACD......it gives BE=EC 1...show that triangle ABE=triangle AEC......it gives <AEB=<AEC=90

pratu043
 3 years ago
Best ResponseYou've already chosen the best response.0I have shown that triangle ABD = ACD, but I don't know how to do the other one.

mukushla
 3 years ago
Best ResponseYou've already chosen the best response.2triangle ABE=triangle AEC because 1...AC=AB 2...BE=EC 3...AE=AE

pratu043
 3 years ago
Best ResponseYou've already chosen the best response.0But we have to prove that BE = EC right?

pratu043
 3 years ago
Best ResponseYou've already chosen the best response.0Perpendicular bisector.

mukushla
 3 years ago
Best ResponseYou've already chosen the best response.2u've shown that triangle ABD=triangle ACD am i right?

pratu043
 3 years ago
Best ResponseYou've already chosen the best response.0sorry if I take a little long to reply.

pratu043
 3 years ago
Best ResponseYou've already chosen the best response.0I mean, its not a side of ABD or ACD.

mukushla
 3 years ago
Best ResponseYou've already chosen the best response.2u r right ... thats not a complete proof... lets think again...

mukushla
 3 years ago
Best ResponseYou've already chosen the best response.2we need to show that triangle ABE=triangle AEC...........

mukushla
 3 years ago
Best ResponseYou've already chosen the best response.2try to find 2 angles equal...and one side equal for that 2 triangle

pratu043
 3 years ago
Best ResponseYou've already chosen the best response.0so that you don't need to scroll up too much.

mukushla
 3 years ago
Best ResponseYou've already chosen the best response.2we proved that triangle ABD=triangle ACD so that... <BAE=<CAE and what is the third condition?

pratu043
 3 years ago
Best ResponseYou've already chosen the best response.0AE is common so triangle AEB = AEC.

pratu043
 3 years ago
Best ResponseYou've already chosen the best response.0But how does that prove that AD is the perpendicular bisector?

pratu043
 3 years ago
Best ResponseYou've already chosen the best response.0We should prove that AD bisects BC and angle AEB = 90 degrees.

mukushla
 3 years ago
Best ResponseYou've already chosen the best response.2it provides BE=EC and <AEB=<AEC but we know that <AEB+<AEC=180

pratu043
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks a lot mukushla!!!
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