anonymous
  • anonymous
Having a conceptual problem why is 0/0 undefined?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@Callisto @TuringTest please help ...
lgbasallote
  • lgbasallote
0/0 is not undefined...it is indeterminate
anonymous
  • anonymous
indeterminate

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anonymous
  • anonymous
what that does mean actually? @lgbasallote
TuringTest
  • TuringTest
this is not an easy question to answer it has to do with different ways you can approach this limit
lgbasallote
  • lgbasallote
the value cannot be determined...thus INdeterminate
anonymous
  • anonymous
Oh no problem @TuringTest , I understand the problem @lgbasallote thanks a lot
lgbasallote
  • lgbasallote
there are a few main reasons why: 1) it conflicts between the rule that a number divided by itself is 1; and the rule that 0 divided by anything is 0. thus it conflicts whether the value is 1 or 0. so you cant determine if it is 1 or 0. 2) another reason is because there are infinite values that will give you 0 when multiplied by 0. so you cant determine which number is the right one.
anonymous
  • anonymous
Well @mathslover Recommend this site .. how to use this?
anonymous
  • anonymous
already sent him info on indeterminate
TuringTest
  • TuringTest
for example\[\lim_{x\to0}\frac xx=1\]but\[\lim_{x\to0}\frac{2x}x=2\]but both are mathematically equivalent to \[\frac00\]in the l;imit hence if we admitted\[\frac00\]into the set of numbers and gave it a value it would be inconsistent in mathematics and destroy the whole system effectively.
TuringTest
  • TuringTest
\[\lim_{x\to0}\frac{x^2}x=0\]etc. it would be an "inconsistent formal system"
anonymous
  • anonymous
to easily understand this concept let's take an example of (10/2) which is same as 5, and (5/5) is same as 1, but we can't say (0/0) as 1 simply because 0 on numerator is equal to zero on denominator, and (0/0) is undefined..... we don't know what it is.
lgbasallote
  • lgbasallote
@SUROJ (0/0) is not undefined
lgbasallote
  • lgbasallote
undefined is x/0
anonymous
  • anonymous
@lgbasallote why x/0 is undefined? curious
lgbasallote
  • lgbasallote
okay let's say for example x = 2 2/0 can you give me a number that when you multiply to 0 the answer is 2?
TuringTest
  • TuringTest
I think that technically both are undefined 1/0 is undefined but *not* an indefinite form 0/0 is an indefinite form. Is it also undefined? I think so...
anonymous
  • anonymous
nope
lgbasallote
  • lgbasallote
i think the best term for 0/0 is indeterminate..
TuringTest
  • TuringTest
any division by zero is undefined, so x/0 is undefined 1/0 undefined and not indefinite 0/0 undefined and indefinite that's my understanding
dumbcow
  • dumbcow
my way of thinking is undefined refers to an infinite number that is not defined but we relatively know its really big or really small(big negative) indeterminate means we have no idea what the value is
TuringTest
  • TuringTest
I meant "indeterminate" when I said "indefinite" :/ so do you say that 1/0 is indeterminate or not?
TuringTest
  • TuringTest
@dumbcow
dumbcow
  • dumbcow
no i would say its not indeterminate because we know the limit of 1/x as x->0 is infinity
anonymous
  • anonymous
1/0 is not indeterminate
TuringTest
  • TuringTest
ok I agree with that just making sure we're all on the same page
anonymous
  • anonymous
0*1 = 0 0*2 = 0 0*dog = 0 0*nitinz570 = 0 can you tell particularly for what values you are getting 0..??
dumbcow
  • dumbcow
the indeterminate forms are: 0/0 inf/inf 0*inf
anonymous
  • anonymous
1/0 is complex infinity
TuringTest
  • TuringTest
0^0 debated at times
anonymous
  • anonymous
\(0^0\) is also undetermined..
anonymous
  • anonymous
yep
anonymous
  • anonymous
indeterminate*
anonymous
  • anonymous
see how the mayan's gave mathematicians more to debate about?
anonymous
  • anonymous
there are 7 indeterminate forms in nature
anonymous
  • anonymous
just check wolfram mathworld.
TuringTest
  • TuringTest
mathematicians debate whether or not \(0^0=1\) or not Euler, for instance, thought it did
anonymous
  • anonymous
0/0, infinity/infinity, 0^infinity, 1^infinity, 0^0, infinity^0, infinity-infinity
anonymous
  • anonymous
if 0^0 =1 then 0/0 = 1 also
TuringTest
  • TuringTest
http://www.faqs.org/faqs/sci-math-faq/specialnumbers/0to0/?PHPSESSID=40fdcce21f158a5d17267b711e395947#b not true panlac
anonymous
  • anonymous
http://mathworld.wolfram.com/Indeterminate.html
TuringTest
  • TuringTest
mathematicians *define* \(0^0=1\) because of a number of arguments btw note that your reference is Thomas and Finney 1996, pp. 220 and 423; Gellert et al. 1989, p. 400 and there are other equally reputable books and references that disagree if you read the article I linked you too, or some of those linked to it.
TuringTest
  • TuringTest
*some* mathematicians - I meant above...
TuringTest
  • TuringTest
it is just very debated ti this day is all I generally treat it as undefined as well
TuringTest
  • TuringTest
to*
anonymous
  • anonymous
yeh. my math professor is one of those who thinks the same way. but she teaches it as indeterminate
TuringTest
  • TuringTest
It makes more sense to me as well, I'm just pointing out the discrepancy out there...
anonymous
  • anonymous
trust me, it does to me also
anonymous
  • anonymous
For x not equal to 0, x/0 is defined (as a number, not necessarily as a limit) in a 1-point compactification of the reals (the projectively extended real numbers) or the complex numbers (the extended complex plane), and is equal to infinity. However, 0/0 (as a number) is still undefined in these settings.
dumbcow
  • dumbcow
btw the limit of x^x as x->0 is 1 , which i believe is a strong argument for equating 0^0 to 1
mathslover
  • mathslover
Nice discussion and also : \[\huge{\mathbb{Welcome}\textbf{To}\mathbb{Open}\textbf{Study}}\]

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