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pratu043

  • 3 years ago

Show that in a quadrilateral ABCD, AB+BC+CA+DA > AC+BD.

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  1. mukushla
    • 3 years ago
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    |dw:1344502321128:dw|

  2. sauravshakya
    • 3 years ago
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    |dw:1344502527479:dw|

  3. sauravshakya
    • 3 years ago
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    take two triangles ABC and triangles BDC

  4. sauravshakya
    • 3 years ago
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    |dw:1344502571798:dw|In triangle ABC,

  5. sauravshakya
    • 3 years ago
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    I think the question is AB+BC+CA+DA > AC+CD

  6. mukushla
    • 3 years ago
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    @pratu043 i think there is a problem with question

  7. mukushla
    • 3 years ago
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    AB+BC+CA+DA > AC+BD --- ---

  8. sauravshakya
    • 3 years ago
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    @pratu043 u there

  9. pratu043
    • 3 years ago
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    Sorry, it is BD not CD.

  10. pratu043
    • 3 years ago
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    help please.

  11. sauravshakya
    • 3 years ago
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    oh i got it

  12. sauravshakya
    • 3 years ago
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    in triangle ABD , AB + DA > BD

  13. pratu043
    • 3 years ago
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    The quadrilateral should be like this: |dw:1344503679049:dw|

  14. sauravshakya
    • 3 years ago
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    in triangle ABD , AB + DA > BD right @pratu043

  15. pratu043
    • 3 years ago
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    How did you get that @sauravshakya?

  16. sauravshakya
    • 3 years ago
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    In a triangle sum of two sides of a triangle is always greater than the third side right?

  17. sauravshakya
    • 3 years ago
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    @pratu043

  18. pratu043
    • 3 years ago
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    Oops, yes I forgot that.

  19. pratu043
    • 3 years ago
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    So what next?

  20. sauravshakya
    • 3 years ago
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    Cancel CA and AC since they are same side..... so u will get AB+BC+DA > BD.

  21. sauravshakya
    • 3 years ago
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    right?

  22. sauravshakya
    • 3 years ago
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    and since AB + BC > BD, AB+BC+DA > BD (thus, proved)

  23. sauravshakya
    • 3 years ago
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    got it?

  24. pratu043
    • 3 years ago
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    But AB+BC+DA > BD is not what we should prove.

  25. jiteshmeghwal9
    • 3 years ago
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    |dw:1344516745619:dw|

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