anonymous
  • anonymous
Show that in a quadrilateral ABCD, AB+BC+CA+DA > AC+BD.
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
|dw:1344502321128:dw|
anonymous
  • anonymous
|dw:1344502527479:dw|
anonymous
  • anonymous
take two triangles ABC and triangles BDC

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
|dw:1344502571798:dw|In triangle ABC,
anonymous
  • anonymous
I think the question is AB+BC+CA+DA > AC+CD
anonymous
  • anonymous
@pratu043 i think there is a problem with question
anonymous
  • anonymous
AB+BC+CA+DA > AC+BD --- ---
anonymous
  • anonymous
@pratu043 u there
anonymous
  • anonymous
Sorry, it is BD not CD.
anonymous
  • anonymous
help please.
anonymous
  • anonymous
oh i got it
anonymous
  • anonymous
in triangle ABD , AB + DA > BD
anonymous
  • anonymous
The quadrilateral should be like this: |dw:1344503679049:dw|
anonymous
  • anonymous
in triangle ABD , AB + DA > BD right @pratu043
anonymous
  • anonymous
How did you get that @sauravshakya?
anonymous
  • anonymous
In a triangle sum of two sides of a triangle is always greater than the third side right?
anonymous
  • anonymous
@pratu043
anonymous
  • anonymous
Oops, yes I forgot that.
anonymous
  • anonymous
So what next?
anonymous
  • anonymous
Cancel CA and AC since they are same side..... so u will get AB+BC+DA > BD.
anonymous
  • anonymous
right?
anonymous
  • anonymous
and since AB + BC > BD, AB+BC+DA > BD (thus, proved)
anonymous
  • anonymous
got it?
anonymous
  • anonymous
But AB+BC+DA > BD is not what we should prove.
jiteshmeghwal9
  • jiteshmeghwal9
|dw:1344516745619:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.