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mynameisjanelle Group Title

In how many ways can a gymnastics team of 4 be chosen from 9 gymnasts?

  • 2 years ago
  • 2 years ago

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  1. mynameisjanelle Group Title
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    dont get this one, could someone show me the steps?

    • 2 years ago
  2. lgbasallote Group Title
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    "chosen" so you use combinations

    • 2 years ago
  3. apple_pi Group Title
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    from 9 choose 4. 9C4 = ...

    • 2 years ago
  4. lgbasallote Group Title
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    arent you missing something?

    • 2 years ago
  5. mynameisjanelle Group Title
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    362880?

    • 2 years ago
  6. lgbasallote Group Title
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    that's 9!

    • 2 years ago
  7. apple_pi Group Title
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    don't forget to divide by all the same combinations (n-r)!

    • 2 years ago
  8. lgbasallote Group Title
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    \[9C4 \implies \frac{9!}{4!(9-4)!}\]

    • 2 years ago
  9. apple_pi Group Title
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    dividing by (n-r)! is what separates the combination formula from the permutation, because you are not counting all the different arrangements

    • 2 years ago
  10. lgbasallote Group Title
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    isnt dividing r! what separates it?

    • 2 years ago
  11. lgbasallote Group Title
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    \[nCr = \frac{n!}{r!(n-r)!}\] \[nPr = \frac{n!}{(n-r)!}\]

    • 2 years ago
  12. lgbasallote Group Title
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    dividing by r! is just the difference i see =))

    • 2 years ago
  13. mynameisjanelle Group Title
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    126!!

    • 2 years ago
  14. lgbasallote Group Title
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    i hope those ! arent factorials :p haha

    • 2 years ago
  15. lgbasallote Group Title
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    anyway yeah. 9C4 = 126

    • 2 years ago
  16. mynameisjanelle Group Title
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    ya:P

    • 2 years ago
  17. apple_pi Group Title
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    Ooops, I meant r! not (n-r)! for all the above posts. Sorry :o

    • 2 years ago
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