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mynameisjanelle

  • 3 years ago

In how many ways can a gymnastics team of 4 be chosen from 9 gymnasts?

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  1. mynameisjanelle
    • 3 years ago
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    dont get this one, could someone show me the steps?

  2. lgbasallote
    • 3 years ago
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    "chosen" so you use combinations

  3. apple_pi
    • 3 years ago
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    from 9 choose 4. 9C4 = ...

  4. lgbasallote
    • 3 years ago
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    arent you missing something?

  5. mynameisjanelle
    • 3 years ago
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    362880?

  6. lgbasallote
    • 3 years ago
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    that's 9!

  7. apple_pi
    • 3 years ago
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    don't forget to divide by all the same combinations (n-r)!

  8. lgbasallote
    • 3 years ago
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    \[9C4 \implies \frac{9!}{4!(9-4)!}\]

  9. apple_pi
    • 3 years ago
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    dividing by (n-r)! is what separates the combination formula from the permutation, because you are not counting all the different arrangements

  10. lgbasallote
    • 3 years ago
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    isnt dividing r! what separates it?

  11. lgbasallote
    • 3 years ago
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    \[nCr = \frac{n!}{r!(n-r)!}\] \[nPr = \frac{n!}{(n-r)!}\]

  12. lgbasallote
    • 3 years ago
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    dividing by r! is just the difference i see =))

  13. mynameisjanelle
    • 3 years ago
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    126!!

  14. lgbasallote
    • 3 years ago
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    i hope those ! arent factorials :p haha

  15. lgbasallote
    • 3 years ago
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    anyway yeah. 9C4 = 126

  16. mynameisjanelle
    • 3 years ago
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    ya:P

  17. apple_pi
    • 3 years ago
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    Ooops, I meant r! not (n-r)! for all the above posts. Sorry :o

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