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In how many ways can a gymnastics team of 4 be chosen from 9 gymnasts?

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dont get this one, could someone show me the steps?
"chosen" so you use combinations
from 9 choose 4. 9C4 = ...

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Other answers:

arent you missing something?
that's 9!
don't forget to divide by all the same combinations (n-r)!
\[9C4 \implies \frac{9!}{4!(9-4)!}\]
dividing by (n-r)! is what separates the combination formula from the permutation, because you are not counting all the different arrangements
isnt dividing r! what separates it?
\[nCr = \frac{n!}{r!(n-r)!}\] \[nPr = \frac{n!}{(n-r)!}\]
dividing by r! is just the difference i see =))
i hope those ! arent factorials :p haha
anyway yeah. 9C4 = 126
Ooops, I meant r! not (n-r)! for all the above posts. Sorry :o

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