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What does it mean by restriced values in wolfram alpha? http://www.wolframalpha.com/input/?i=integrate+1%2F%2810-v%2F5%29
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
where?
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Click the show steps then you'll see it
lgbasallote
  • lgbasallote
im guessing it would be the value of v that would make the denominator equal to 0

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lgbasallote
  • lgbasallote
you cant have a denominator of zero right?
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That's weird because even the solution here http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20%289709%29/9709_w11_ms_51.pdf ended up \[-5 \log (v-50)+c\] but not \[-5 \log \left(10-\frac{v}{5}\right)+c\]
lgbasallote
  • lgbasallote
hmmm wolfram does a lot of funny business =_=
anonymous
  • anonymous
um, v cannot equal 50. try evaluating your original expression with v = 50.
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v can be 50, ln(0)=1
lgbasallote
  • lgbasallote
ln (1) = 0
lgbasallote
  • lgbasallote
ln (0) = infinity
lgbasallote
  • lgbasallote
ln e = 1
anonymous
  • anonymous
even your original function: 1/(10-v/5) what do you get when v = 50?
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=1%2F%2810-v%2F5%29 Look what would the integral be at v = 50? v = 50 is a vertical asymptote.
UnkleRhaukus
  • UnkleRhaukus
how did you get ln (0) is infinity at @lgbasallote ?
lgbasallote
  • lgbasallote
hmm read the post lol...i didnt get ln (0) i was explaining that ln (0) is not 1
UnkleRhaukus
  • UnkleRhaukus
ln (0) is not infinity either
lgbasallote
  • lgbasallote
well...close enough
UnkleRhaukus
  • UnkleRhaukus
|dw:1344507971374:dw|
lgbasallote
  • lgbasallote
depends if 0+ or 0-...but i just generalized as infinity =))
lgbasallote
  • lgbasallote
my point was it's not 1 =_=
UnkleRhaukus
  • UnkleRhaukus
infinity is not close enough to negative infinity

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