Which statement best compares a square and a rhombus?
B, right?

- anonymous

Which statement best compares a square and a rhombus?
B, right?

- jamiebookeater

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- anonymous

A rhombus has all angles equal to 90° but a square has opposite angles equal.
A rhombus has diagonals which are unequal but a square has diagonals which are equal.
A rhombus has equal diagonals but a square has unequal diagonals.
A rhombus has non perpendicular diagonals but a square has perpendicular diagonal.

- anonymous

The first one is definitely not, a rhombus's angles are not all 90°
The last one is wrong, because a rhombus has perpendicular diagonals.
The third one is wrong, because a square certainly has equal diagonals.
So yes, it is B.
Just think over the properties of a rhombus and square

- anonymous

Yay! Thanks!

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## More answers

- anonymous

@apple_pi can you help me with one more?

- anonymous

Sure...

- anonymous

When an altitude is drawn to the hypotenuse of a right triangle, the lengths of the segments of the hypotenuse are 16 and 25. What is the length of the altitude?

- anonymous

Ahh, let me draw

- anonymous

I know what an altitude is, but this one I just don't get at all...

- anonymous

Ok, so like this?

##### 1 Attachment

- anonymous

yes... how did you do that?

- anonymous

Adobe Illustrator

- anonymous

and AD is the altitude right?

- anonymous

Yep

- anonymous

Ahhhh I used that program a lot... now it's photoshop, flash, and premiere pro for me haha... anyways.......

- anonymous

Do you get that AD splits ∆ABC into two similar triangles which are similar to the large triangle?

- anonymous

yeah

- anonymous

Wait, i'm thinking

- anonymous

k

- anonymous

Ok, so then AB/BC = BD/AD right?

- anonymous

So then AB/41 = 25/AD

- anonymous

okay

- anonymous

Similarly, AC/BC = DC/AD right?

- anonymous

AC/41 = 16/AD

- anonymous

right

- anonymous

now make AD the subject in both of these

- anonymous

how?

- anonymous

for the first one, AD = 16*41/AC

- anonymous

okay

- anonymous

hmm, I just lost it

- anonymous

@lgbasallote any idea?

- anonymous

@Callisto ?

- anonymous

Am I on the right track here?

- Callisto

Blah...
@Sunshine447 Post close the question and start a new post for a new question. Thanks!

- anonymous

k

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