anonymous
  • anonymous
When an altitude is drawn to the hypotenuse of a right triangle, the lengths of the segments of the hypotenuse are 16 and 25. What is the length of the altitude?
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Ahh got it!
anonymous
  • anonymous
BD/AD = AB/AC CD/AD = AC/AB (inverse of above) so BD/AD = AD/CD
anonymous
  • anonymous
BD*CD=AD^2 Now can you do it?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
@Sunshine447
Callisto
  • Callisto
@apple_pi I would do it in this way |dw:1344514762278:dw| a^2+b^2 = (16+25)^2 a^2 = c^2 + 16^2 -(1) b^2 = c^2 + 25^2 -(2) (1) + (2) a^2 + b^2 = c^2 + 16^2 + c^2 + 25^2 (16+25)^2 = 2c^2 + 16^2 + 25^2
Callisto
  • Callisto
Solve the equation...
anonymous
  • anonymous
Nice @Callisto, but does my way work?
anonymous
  • anonymous
Oh, sorry forgot this is a new thread
Callisto
  • Callisto
It works too :)
anonymous
  • anonymous
Did you know this can be used to prove Pythagoras' Theorem?
Callisto
  • Callisto
Not sure, the first time I saw this method was in a circle problem. Someone taught me this property... :|
anonymous
  • anonymous
Hey @Sunshine447! Here's how to do it!

Looking for something else?

Not the answer you are looking for? Search for more explanations.