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Simplify: (40a/b^2-5b+4) / (5a^2/2b-2)

Mathematics
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40a / (b-1)*(b-4) / 5a^2 / 2(b-1) 40 cancels with 5 leaving 8 a^2 cancels with a leaving a in denominator b-1 cancels with b-1 so left with 8/b-4 / a/2 invert and multiply 16/ab--4a
can you understand ? @jchavez96
Sorta , I'm working on it right now . @ashna

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Other answers:

okay :)
These are my options ashna , I'm having trouble figuring it out .
1 Attachment
4th option is right , you want to know how , or do you know ?
Can you explain it to me please ?
now take b^2-5b+4 and simplify it like u do spliting the middle term so....b^2-5b+4 b(b-4)-1(b-4)
(b-1) (b-4)
now {40a/(b-1)(b-4)}/{5a^2/2b-2}
take the main denominater in reciprocal form then cancel 40a with 5a^2
now 16b-16/(b-1)(b-4) = 16(b-1)/(b-1)(b-4)
cancel b-1 u'll get opt4
(i.e) = 16/b-4
@jchavez96 understood now ?
I see . . . Thank you !! What is the b=4 for ? The one with the equal sign crossed out ?
dat's b not equal to 4 just substute b as 4 u wont get correct answer
understood @jchavez96
Yes ! Thank you @ashna ! I really appreciate it !
no mention :)

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