jchavez96
Simplify: (40a/b^2-5b+4) / (5a^2/2b-2)
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ashna
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40a / (b-1)*(b-4) / 5a^2 / 2(b-1)
40 cancels with 5 leaving 8
a^2 cancels with a leaving a in denominator
b-1 cancels with b-1
so left with
8/b-4 / a/2
invert and multiply
16/ab--4a
ashna
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can you understand ? @jchavez96
jchavez96
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Sorta , I'm working on it right now . @ashna
ashna
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okay :)
jchavez96
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These are my options ashna , I'm having trouble figuring it out .
jchavez96
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@ashna
ashna
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4th option is right , you want to know how , or do you know ?
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@jchavez96
jchavez96
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Can you explain it to me please ?
ashna
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now take b^2-5b+4 and simplify it
like u do spliting the middle term
so....b^2-5b+4
b(b-4)-1(b-4)
ashna
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(b-1) (b-4)
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now {40a/(b-1)(b-4)}/{5a^2/2b-2}
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take the main denominater in reciprocal form
then cancel 40a with 5a^2
ashna
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now 16b-16/(b-1)(b-4) = 16(b-1)/(b-1)(b-4)
ashna
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cancel b-1
u'll get opt4
ashna
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(i.e) = 16/b-4
ashna
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@jchavez96 understood now ?
jchavez96
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I see . . . Thank you !! What is the b=4 for ? The one with the equal sign crossed out ?
jchavez96
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@ashna
ashna
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dat's b not equal to 4
just substute b as 4
u wont get correct answer
ashna
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understood @jchavez96
jchavez96
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Yes ! Thank you @ashna ! I really appreciate it !
ashna
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no mention :)