## jchavez96 3 years ago Simplify: (40a/b^2-5b+4) / (5a^2/2b-2)

1. ashna

40a / (b-1)*(b-4) / 5a^2 / 2(b-1) 40 cancels with 5 leaving 8 a^2 cancels with a leaving a in denominator b-1 cancels with b-1 so left with 8/b-4 / a/2 invert and multiply 16/ab--4a

2. ashna

can you understand ? @jchavez96

3. jchavez96

Sorta , I'm working on it right now . @ashna

4. ashna

okay :)

5. jchavez96

These are my options ashna , I'm having trouble figuring it out .

6. jchavez96

@ashna

7. ashna

4th option is right , you want to know how , or do you know ?

8. ashna

@jchavez96

9. jchavez96

Can you explain it to me please ?

10. ashna

now take b^2-5b+4 and simplify it like u do spliting the middle term so....b^2-5b+4 b(b-4)-1(b-4)

11. ashna

(b-1) (b-4)

12. ashna

now {40a/(b-1)(b-4)}/{5a^2/2b-2}

13. ashna

take the main denominater in reciprocal form then cancel 40a with 5a^2

14. ashna

now 16b-16/(b-1)(b-4) = 16(b-1)/(b-1)(b-4)

15. ashna

cancel b-1 u'll get opt4

16. ashna

(i.e) = 16/b-4

17. ashna

@jchavez96 understood now ?

18. jchavez96

I see . . . Thank you !! What is the b=4 for ? The one with the equal sign crossed out ?

19. jchavez96

@ashna

20. ashna

dat's b not equal to 4 just substute b as 4 u wont get correct answer

21. ashna

understood @jchavez96

22. jchavez96

Yes ! Thank you @ashna ! I really appreciate it !

23. ashna

no mention :)