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LaurenAshley1201

  • 2 years ago

Which expression is equal to sec x° multiplied by cot x°?

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  1. LaurenAshley1201
    • 2 years ago
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    hypotenuse ÷ adjacent adjacent ÷ hypotenuse opposite ÷ adjacent hypotenuse ÷ opposite

  2. KALYNNKANE
    • 2 years ago
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    The graph below compares the total cost c of renting a car for d days with two different companies. Based on the information in the graph, which statement is FALSE? For a two-day rental, the price is the same with both companies. For a four-day rental, ReliaRent is cheaper. For a three-day rental, Trust Rentals is more expensive. For a one-day rental, ReliaRent is cheaper.

  3. msayer3
    • 2 years ago
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    try putting sec and cot in terms of trig properties i.e.) sin = opp/hyp and such

  4. satellite73
    • 2 years ago
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    man you are all over the place today solving equations, and now trig?! what kind of class is this?

  5. satellite73
    • 2 years ago
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    \[\sec(x)=\frac{hyp}{adj}\] \[\cot(x)=\frac{adj}{opp}\] multiply and cancel

  6. waterineyes
    • 2 years ago
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    \[\sec(x) = \frac{1}{\cos(x)}\] \[\cot(x) = \frac{\cos(x)}{\sin(x)}\] \[\implies \frac{1}{\cos(x)} \times \frac{\cos(x)}{\sin(x)} \implies \frac{1}{\sin(x)} \implies cosec(x)\]

  7. satellite73
    • 2 years ago
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    \[\frac{hyp}{adj}\times \frac{adj}{opp}=\frac{hyp}{opp}\]

  8. satellite73
    • 2 years ago
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    also what @waterineyes said, but you are asked for the ratios \[\csc(x)=\frac{hyp}{opp}\] too

  9. waterineyes
    • 2 years ago
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    \[cosec(x) = \frac{Hypotenuse}{Opposite}\]

  10. waterineyes
    • 2 years ago
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    I am bit slow in typing..

  11. LaurenAshley1201
    • 2 years ago
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    thankyou SOOOOO much!

  12. waterineyes
    • 2 years ago
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    Welcome dear..

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