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anonymous
 3 years ago
Which expression is equal to sec x° multiplied by cot x°?
anonymous
 3 years ago
Which expression is equal to sec x° multiplied by cot x°?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hypotenuse ÷ adjacent adjacent ÷ hypotenuse opposite ÷ adjacent hypotenuse ÷ opposite

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The graph below compares the total cost c of renting a car for d days with two different companies. Based on the information in the graph, which statement is FALSE? For a twoday rental, the price is the same with both companies. For a fourday rental, ReliaRent is cheaper. For a threeday rental, Trust Rentals is more expensive. For a oneday rental, ReliaRent is cheaper.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0try putting sec and cot in terms of trig properties i.e.) sin = opp/hyp and such

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0man you are all over the place today solving equations, and now trig?! what kind of class is this?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sec(x)=\frac{hyp}{adj}\] \[\cot(x)=\frac{adj}{opp}\] multiply and cancel

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sec(x) = \frac{1}{\cos(x)}\] \[\cot(x) = \frac{\cos(x)}{\sin(x)}\] \[\implies \frac{1}{\cos(x)} \times \frac{\cos(x)}{\sin(x)} \implies \frac{1}{\sin(x)} \implies cosec(x)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{hyp}{adj}\times \frac{adj}{opp}=\frac{hyp}{opp}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0also what @waterineyes said, but you are asked for the ratios \[\csc(x)=\frac{hyp}{opp}\] too

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[cosec(x) = \frac{Hypotenuse}{Opposite}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I am bit slow in typing..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thankyou SOOOOO much!
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