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  • 3 years ago

If \[x/aCOS \alpha+y/bSIN \alpha =1 and x/aCOS \beta+y/bSIN \beta = 1\] and \[COS \alpha COS \beta /a ^{2}+SIN \alpha SIN \beta/b ^{2} = 0\] Then prove that a)\[x ^{2}+y ^{2}=a ^{2}+b ^{2}\] and b) \[\tan \alpha \tan \beta = b ^{2}(x ^{2}-a ^{2})/a ^{2}(y ^{2}-b ^{2})\]

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  1. robinfr93
    • 3 years ago
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    Can somebody help me solve this???

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