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## anonymous 4 years ago If $x/aCOS \alpha+y/bSIN \alpha =1 and x/aCOS \beta+y/bSIN \beta = 1$ and $COS \alpha COS \beta /a ^{2}+SIN \alpha SIN \beta/b ^{2} = 0$ Then prove that a)$x ^{2}+y ^{2}=a ^{2}+b ^{2}$ and b) $\tan \alpha \tan \beta = b ^{2}(x ^{2}-a ^{2})/a ^{2}(y ^{2}-b ^{2})$

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1. anonymous

Can somebody help me solve this???

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