anonymous
  • anonymous
i'm stuck i need help factoring out this> 7k^2+9k
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
each has a common factor of \(k\) so you can "factor it out"
anonymous
  • anonymous
so i keep getting 16 but i'm not sure if thats right
Callisto
  • Callisto
It's not correct. When you take out the common factor k, what is left for each term?

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anonymous
  • anonymous
7 and 9
lgbasallote
  • lgbasallote
remember.. \[7k^2 = 7k \times k\]
anonymous
  • anonymous
ok
anonymous
  • anonymous
so i have 63
Callisto
  • Callisto
You cannot multiply the terms... One example: factor x^2 + 2x In this case, x is the common factor. Take it out and group the rest of the terms, that is x^2 + 2x = x (x) + 2(x) = x ( x+2) Can you try again for your question?
anonymous
  • anonymous
so is k(7k+9) correct
Callisto
  • Callisto
Yes.
anonymous
  • anonymous
thanks

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