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satellite73Best ResponseYou've already chosen the best response.2
each has a common factor of \(k\) so you can "factor it out"
 one year ago

lovinglyhatedBest ResponseYou've already chosen the best response.0
so i keep getting 16 but i'm not sure if thats right
 one year ago

CallistoBest ResponseYou've already chosen the best response.0
It's not correct. When you take out the common factor k, what is left for each term?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
remember.. \[7k^2 = 7k \times k\]
 one year ago

CallistoBest ResponseYou've already chosen the best response.0
You cannot multiply the terms... One example: factor x^2 + 2x In this case, x is the common factor. Take it out and group the rest of the terms, that is x^2 + 2x = x (x) + 2(x) = x ( x+2) Can you try again for your question?
 one year ago

lovinglyhatedBest ResponseYou've already chosen the best response.0
so is k(7k+9) correct
 one year ago
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