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satellite73 Group TitleBest ResponseYou've already chosen the best response.2
each has a common factor of \(k\) so you can "factor it out"
 2 years ago

lovinglyhated Group TitleBest ResponseYou've already chosen the best response.0
so i keep getting 16 but i'm not sure if thats right
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
It's not correct. When you take out the common factor k, what is left for each term?
 2 years ago

lovinglyhated Group TitleBest ResponseYou've already chosen the best response.0
7 and 9
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
remember.. \[7k^2 = 7k \times k\]
 2 years ago

lovinglyhated Group TitleBest ResponseYou've already chosen the best response.0
so i have 63
 2 years ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
You cannot multiply the terms... One example: factor x^2 + 2x In this case, x is the common factor. Take it out and group the rest of the terms, that is x^2 + 2x = x (x) + 2(x) = x ( x+2) Can you try again for your question?
 2 years ago

lovinglyhated Group TitleBest ResponseYou've already chosen the best response.0
so is k(7k+9) correct
 2 years ago

lovinglyhated Group TitleBest ResponseYou've already chosen the best response.0
thanks
 2 years ago
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