lsugano
HELP what is the phase shift of 3sin(x/2 + pi)
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SUROJ
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pi
SUROJ
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I guess
lsugano
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how did you get that??
SUROJ
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see pi inside sine function
lsugano
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yes..
SUROJ
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that's called phase shift
SUROJ
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or phase change
lsugano
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the phase shift...isnt its -c/b so wouldnt it be -pi/1??
ganeshie8
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Asin(Bx - C)
phase shift = C/B
lsugano
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wait...istn it -C/B
ganeshie8
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yes you're right !
for,
Asin(Bx + C)
phase shift = -C/B
ganeshie8
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3sin(x/2 + pi)
here B = 1/2, C = pi
just plugin :)
lsugano
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okay so since its 3sin(x/2 + pi)
lsugano
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1/2 / pi?
lsugano
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oh other way around i meant!
ganeshie8
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-C/B = -pi/1/2 = -2pi
lsugano
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yes!! thank you!!
ganeshie8
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np..
just remember that, since coefficient of x is a fraction, here, its period is more. and hence phase difference also will be more than the the constant term(pi here)
melmel
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.33 i think