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hann()
Group Title
What is the value of the y variable in the solution to the following system of equations?
5x + 4y = 1
4x + 3y = 1
A 7
B 7
C 9
D 9
 one year ago
 one year ago
hann() Group Title
What is the value of the y variable in the solution to the following system of equations? 5x + 4y = 1 4x + 3y = 1 A 7 B 7 C 9 D 9
 one year ago
 one year ago

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hann() Group TitleBest ResponseYou've already chosen the best response.0
I don't know how to do it that's why I need the answers
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.0
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 one year ago

hbaldon Group TitleBest ResponseYou've already chosen the best response.0
I won't give you answer but I can give you hints on how to solve this.
 one year ago

muhammad9t5 Group TitleBest ResponseYou've already chosen the best response.0
5x + 4y = 1..................................1 4x + 3y = 1.......................2 From equation 1 5x=14y x=14y/5 now put into 2nd equ then get value of y . After getting value of y then put into 1st equ to get value of x.
 one year ago

apple_pi Group TitleBest ResponseYou've already chosen the best response.2
Example: 5x+y=31 [1] x2y=7 [2] rearrange [1] to make y the subject. y = 31  5x rearrange [2] to make y the subject. 2y = 7  x 2y = 7 + x y = (7 + x)/2 Now equate your two expressions for y. 31  5x = (7+x)/2 2(31  5x) = 7 + x 62  10x = 7 + x 55 = 11x therefore x = 5 Now sub in x = 5 into [1] or [2] (doesn't matter) [2] > (5)2y = 7 2y = 12 2y = 12 y = 6 So there you have it... x = 5, y = 6. Now follow my approach on your problem
 one year ago

morgenta Group TitleBest ResponseYou've already chosen the best response.0
Another approach could be the following: If you multiply the 1st equation by 4 and the second equation by 5, you'll get two equations that both have 20x in them. You can isolate 20X on both and then combine to get a single equation with only Y as the unknown (which is what you're solving for)
 one year ago

85295james Group TitleBest ResponseYou've already chosen the best response.0
do you need help
 one year ago
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