integrate (from -1 to 1) x^2+x+1 (dx)

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integrate (from -1 to 1) x^2+x+1 (dx)

Mathematics
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|dw:1344593806371:dw|
i am getting 5/3 ..
i hope you do not need that method again :PPPPPPPPPPPPPPPPP

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Other answers:

|dw:1344593826776:dw|
|dw:1344593866185:dw|
|dw:1344593835846:dw|
m i right?
you should have 8/3 :P
you missed the 1
|dw:1344593935823:dw|
|dw:1344593979072:dw|
where did i miss the 1 ? : 1/3 + 1/3 + 1/2 - 1/2 + 1 5/3
8/3 is the correct answer
|dw:1344594005970:dw|
Oh k so u mean another 1
2/3 + 2 = 8/3
yup
but i dont get that how will we get another 1 : \[\large{[\frac{x^3}{3}](-1 to1)+[\frac{x^2}{2}](-1 to 1)+1}\] that 1 ( last term) should be single
|dw:1344637291535:dw|
since : |dw:1344594117232:dw|
i missed two under x^2
gimme a medal
yes now integrate each term.
integration of 1 is x ! if you take its derivative you get 1 back :)
right i got it @sami-21 thanks a lot
seems all right ... |dw:1344594217239:dw|
yw:)
right .. thanks @experimentX also
np :)

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