mathslover
integrate (from 1 to 1) x^2+x+1 (dx)



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mathslover
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dw:1344593806371:dw

mathslover
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i am getting 5/3 ..

sami21
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i hope you do not need that method again :PPPPPPPPPPPPPPPPP

Hashir
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dw:1344593826776:dw

Hashir
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dw:1344593866185:dw

mathslover
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dw:1344593835846:dw

mathslover
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m i right?

sami21
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you should have 8/3 :P

sami21
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you missed the 1

Hashir
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dw:1344593935823:dw

Hashir
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dw:1344593979072:dw

mathslover
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where did i miss the 1 ? :
1/3 + 1/3 + 1/2  1/2 + 1
5/3

Hashir
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8/3 is the correct answer

mathslover
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dw:1344594005970:dw

mathslover
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Oh k so u mean another 1

mathslover
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2/3 + 2 = 8/3

sami21
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yup

mathslover
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but i dont get that how will we get another 1 :
\[\large{[\frac{x^3}{3}](1 to1)+[\frac{x^2}{2}](1 to 1)+1}\]
that 1 ( last term) should be single

sami21
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dw:1344637291535:dw

mathslover
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since :
dw:1344594117232:dw

sami21
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i missed two under x^2

Hashir
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gimme a medal

sami21
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yes now integrate each term.

sami21
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integration of 1 is x !
if you take its derivative you get 1 back :)

mathslover
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right i got it @sami21 thanks a lot

experimentX
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seems all right ... dw:1344594217239:dw

sami21
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yw:)

mathslover
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right .. thanks @experimentX also

experimentX
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np :)