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mathslover

  • 3 years ago

integrate (from -1 to 1) x^2+x+1 (dx)

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  1. mathslover
    • 3 years ago
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    |dw:1344593806371:dw|

  2. mathslover
    • 3 years ago
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    i am getting 5/3 ..

  3. sami-21
    • 3 years ago
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    i hope you do not need that method again :PPPPPPPPPPPPPPPPP

  4. Hashir
    • 3 years ago
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    |dw:1344593826776:dw|

  5. Hashir
    • 3 years ago
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    |dw:1344593866185:dw|

  6. mathslover
    • 3 years ago
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    |dw:1344593835846:dw|

  7. mathslover
    • 3 years ago
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    m i right?

  8. sami-21
    • 3 years ago
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    you should have 8/3 :P

  9. sami-21
    • 3 years ago
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    you missed the 1

  10. Hashir
    • 3 years ago
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    |dw:1344593935823:dw|

  11. Hashir
    • 3 years ago
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    |dw:1344593979072:dw|

  12. mathslover
    • 3 years ago
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    where did i miss the 1 ? : 1/3 + 1/3 + 1/2 - 1/2 + 1 5/3

  13. Hashir
    • 3 years ago
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    8/3 is the correct answer

  14. mathslover
    • 3 years ago
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    |dw:1344594005970:dw|

  15. mathslover
    • 3 years ago
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    Oh k so u mean another 1

  16. mathslover
    • 3 years ago
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    2/3 + 2 = 8/3

  17. sami-21
    • 3 years ago
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    yup

  18. mathslover
    • 3 years ago
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    but i dont get that how will we get another 1 : \[\large{[\frac{x^3}{3}](-1 to1)+[\frac{x^2}{2}](-1 to 1)+1}\] that 1 ( last term) should be single

  19. sami-21
    • 3 years ago
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    |dw:1344637291535:dw|

  20. mathslover
    • 3 years ago
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    since : |dw:1344594117232:dw|

  21. sami-21
    • 3 years ago
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    i missed two under x^2

  22. Hashir
    • 3 years ago
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    gimme a medal

  23. sami-21
    • 3 years ago
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    yes now integrate each term.

  24. sami-21
    • 3 years ago
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    integration of 1 is x ! if you take its derivative you get 1 back :)

  25. mathslover
    • 3 years ago
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    right i got it @sami-21 thanks a lot

  26. experimentX
    • 3 years ago
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    seems all right ... |dw:1344594217239:dw|

  27. sami-21
    • 3 years ago
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    yw:)

  28. mathslover
    • 3 years ago
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    right .. thanks @experimentX also

  29. experimentX
    • 3 years ago
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    np :)

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