moongazer
let x=4
x^4 = 256
is this correct?



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moongazer
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not
x^4 = 256
because this x^4 means
1(4)^4 not (4)^4

moongazer
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Is it correct?

Yahoo!
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nop

Yahoo!
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it is 256

TheViper
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(x)^4=256 & (x^4)=256

Yahoo!
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becoz instead of x u r giving 4

TheViper
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Does that help @moongazer ??

Yahoo!
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4 * 4 * 4 * 4=

TheViper
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Becoz according to BODMAS rule first we solve brackets :)

moongazer
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so
x^4 = 256
is correct right?

Yahoo!
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but it is like this (4)^4

moongazer
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But there is no parenthesis ?

moongazer
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so it is like 1(x)^4

Yahoo!
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or wat is x*x*x*x

Yahoo!
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nw give x=4

Yahoo!
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wat will the answer


Yahoo!
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just think like that

Yahoo!
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x^4=x*x*x*x

moongazer
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isn't that
\[4^2 \neq (4)^2\]

moongazer
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???

Yahoo!
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why both r same

moongazer
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no it is not

Yahoo!
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why>>>>>>


Yahoo!
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ok.....@moongazer nw tell is this correct or not
x^4=x*x*x*x


Yahoo!
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@moongazer

moongazer
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That is wrong I think.

lgbasallote
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x^4 = 256
for the record...

apple_pi
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indeed

moongazer
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that's the question I am asking :)

lgbasallote
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so i guess it's down to a 2on2

Yahoo!
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why //

Yahoo!
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@lgbasallote x^4=x*x*x*x

apple_pi
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@Yahoo! this is (x^4) not (x)^4

lgbasallote
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because the exponent just affects the nearest base

Yahoo!
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look his question it is just x^4

lgbasallote
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exactly

lgbasallote
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the ^4 is just on x...not on  too

moongazer
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because x^4 is like 1(x)^4
not (x)^4
I think this is the explanation?

Yahoo!
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i would say if (x)^4=256 & (x^4)=256

lgbasallote
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x^4 = (x^4)

Yahoo!
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so wat is 2^2

lgbasallote
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4

moongazer
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@Yahoo! (1)(4)
so 4

apple_pi
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2^2 = 1 (2^2) = 1 * 4 = 4


apple_pi
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when there is a minus, do all the stuff before minusing

Yahoo!
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hey ..... it is like this (x)^4=256 & (x^4)=256



Yahoo!
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(x)^4=256 x^4 = 256 ................ agreed

lgbasallote
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lol