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anonymous
 4 years ago
Solve the following system of equations.
2a – 3b + c = 10
2a – 2b – 2c = 2
a + 3b + 2c = –1
anonymous
 4 years ago
Solve the following system of equations. 2a – 3b + c = 10 2a – 2b – 2c = 2 a + 3b + 2c = –1

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Ghazi
 4 years ago
Best ResponseYou've already chosen the best response.0use determinant to solve above equation

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1there are different methods that all come to the same results; since you have not defined a method, the determinant is suitable

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the determinant is kidna useless you can tell if it's not factorable once you have the equation narrowed to 2 variables.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just use substitution :D!

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1ugh, substitution on these takes forever!!

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1you scale the eqauations so that you can combine them and eliminate one of more of the variables

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1R1, 2a – 3b + c = 10 R2, 2a – 2b – 2c = 2 R3, a + 3b + 2c = –1 R3(2), R2(1) R1, 2a – 3b + c = 10 R2, 2a + 2b + 2c =2 R3, 2a 6b 4c = 2 R1+R2, and R1+R3 R1, 2a – 3b + c = 10 R2, 0  b + 3c = 8 R3, 0  9b  3c = 12 R2(9) R1, 2a – 3b + c = 10 R2, 0 +9b 27c = 72 R3, 0  9b  3c = 12 R2 + R3 R1, 2a – 3b + c = 10 R2, 0 +9b 27c = 72 R3, 0 + 0  30c =60

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1R1, 2a – 3b + (2) = 10 R2, 0 +9b 27(2) = 72 R1, 2a – 3b = 102 R2, 0 +9b = 72+54 b = 18/9 = 2 R1, 2a – 3(2) = 8 R1, 2a + 6 = 8 a = (86)/2 = 1

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.12a – 3b + c = 10 1 2 2  2 + 6 + 2 = 10 2a – 2b – 2c = 2 1 2 2  2 + 4  4 = 2 a + 3b + 2c = –1 1 2 2  1 6 + 4 = 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wow that is a lot of work i do not like these so much do you?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1it takes longer to show the work than it does to actually get the answer :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thankyou for ur help!

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i hope it was helpful :)
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