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\[\frac{dy}{dt} = 2 cm/\sec\]
\[\frac{dx}{dt} = 3 cm/\sec\]
\[determine \frac{dA}{dt}\]

sorry wrote that wrong, should be -2cm/sec

i need the area value at any instant in term of "t"

A(t) = (1/2)(20-2t)(15+3t)

\[\frac{d}{dt}A(t)= \frac{d}{dt}\frac{1}{2}*(20-2t)(15+3t)\]