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anonymous
 4 years ago
exact values for secx=2/sqrt3
anonymous
 4 years ago
exact values for secx=2/sqrt3

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Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.1\[secx = \frac{2}{\sqrt{3}} \] \[secx = \frac{1}{cosx} \]

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.1I think that you're able to do it now..

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{cosx} = \frac{2}{\sqrt{3}} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no you'll have to explain a bit better than that, i can tell you the answer is 5pi/6 and 5pi/6 but im not sure how to get there

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{cosx} = \frac{2}{\sqrt{3}} => \sqrt{3} = 2cosx\] you should be able to do it now :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks ill keep trying, would i b using the fourth quadrant to draw this

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1344660849255:dw since cosx is a negative; so you will use the quadrants that i marks

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that getting clearer for me, now if you could just name the angles with the answers i gave before i might be able to complete the puzzle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think the angle has to be in one quadrant or the other

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oops i gave you the wrong answer a moment ago, the correct answer is pi/3 and 2pi/3, maybe that will help

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.1hmm; i dont know how to explain sorry \[ cosx = \frac{\sqrt{3}}{2} => x = \frac{\pi}{6} + \pi => \frac{7\pi}{6} \]

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1344662088473:dw \[ x = \pi  \frac{\pi}{6} = \frac{5\pi}{6}\]

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.1wait something looks wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes have a look back a couple of replies the answer is pi/3 and 2pi/3, once again i am sorry bi gave you the answer to a different question originally

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is but i gave you the answer to a different question originaly

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.1i doubled checked; i dont think i made any mistake...wait you have me the answers from a different question?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i gotta tell you that is an amazing effort to come up with a correct answer to a question that i gave the incorrect answer to

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.1you just tricked me with a wrong answer?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i promise it was an accident im working on 4 equations at a time here, cramming for an exam in the following week, but now that i gave you the correct answer pi/3 and 2pi/3 it should be easy for you to show me, once again im sorry for that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are you still there mimi x3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0come on mimi your my only hope here, where are you

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can i know the question and the answer please because I don't wanna stuff up because of the confusion up above lol i might be able to help

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sec (x) = 2/\sqrt{3} \] \[1/\cos(x) = 2/\sqrt{3}\] Flip both sides of the equation to get cos(x) on top: \[\cos(x) = \sqrt{3}/2\] Take arccos of both sides, you get \[x=\cos^{1} (\sqrt{3}/2)\] \[x=\pi/6\] Then you know that the range and domain of arccos is only between 0 and pi so that's all the angles you are looking for. And we also know cos is negative so it must be in 2nd or 3rd quadrant. So that leaves us with the 2nd quadrant and the answer, \[x = \pi(\pi/6)\] \[x= 5\pi/6\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0aw man, how do you do fractions in this thing? i hate forward slashes as fractions .

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.1ohh no no. the answer the i typed above is correct. i dont think that its allowed to be (pi/6) and for fractions \frac{..}{..}
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