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\[secx = -\frac{2}{\sqrt{3}} \]
\[secx = \frac{1}{cosx} \]

I think that you're able to do it now..

\[\frac{1}{cosx} = -\frac{2}{\sqrt{3}} \]

well cross multiply

\[\frac{1}{cosx} = \frac{-2}{\sqrt{3}} => \sqrt{3} = -2cosx\]
you should be able to do it now :)

thanks ill keep trying, would i b using the fourth quadrant to draw this

|dw:1344660849255:dw|
since cosx is a negative; so you will use the quadrants that i marks

i think the angle has to be in one quadrant or the other

|dw:1344662088473:dw|
\[ x = \pi
- \frac{\pi}{6}
= \frac{5\pi}{6}\]

wait something looks wrong

that is but i gave you the answer to a different question originaly

what???

you just tricked me with a wrong answer?

are you still there mimi x3

come on mimi your my only hope here, where are you

aw man, how do you do fractions in this thing? i hate forward slashes as fractions -.-