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Very confused on these particular problems...no clue what it's talking about...
 one year ago
 one year ago
Very confused on these particular problems...no clue what it's talking about...
 one year ago
 one year ago

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CalcmathleteBest ResponseYou've already chosen the best response.0
@ganeshie8 I figured out C(x), but I don't get P(x)
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
For 16th question, i think P(X) = 4C2
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
the two element group...say there are 4 elements,ABCD,there will be 16 2 element grp,AA,AB,AC,....DD....but if repetition like AA are not allowed,then there will be 12...and if AB and BA are considered same ,then there will be 6....
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
I am getting B for the first one.
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
Because I did xP2 = P(x) and (n  1)! = C(x)
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
Or would it be xC2 = P(x)?
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
oh i see... but i guess forming 2 element groups involves just choosing elements, order doesnt matter...
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
Oh ok...then I get D for 16 and B for 17. I ddin't realize that, I was still thinking about the other part of the problem.
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
if order doe not matter,then AB and BA are same,then use xC2
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
Ok, then it would be: 16. D 17. B ?
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
yeah i guess that it.... .
 one year ago

CalcmathleteBest ResponseYou've already chosen the best response.0
Alright. Thanks :)
 one year ago
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