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Calcmathlete Group Title

Very confused on these particular problems...no clue what it's talking about...

  • 2 years ago
  • 2 years ago

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  1. Calcmathlete Group Title
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    • 2 years ago
  2. Calcmathlete Group Title
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    @ganeshie8 I figured out C(x), but I don't get P(x)

    • 2 years ago
  3. ganeshie8 Group Title
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    For 16th question, i think P(X) = 4C2

    • 2 years ago
  4. hartnn Group Title
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    the two element group...say there are 4 elements,ABCD,there will be 16 2 element grp,AA,AB,AC,....DD....but if repetition like AA are not allowed,then there will be 12...and if AB and BA are considered same ,then there will be 6....

    • 2 years ago
  5. Calcmathlete Group Title
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    I am getting B for the first one.

    • 2 years ago
  6. Calcmathlete Group Title
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    Because I did xP2 = P(x) and (n - 1)! = C(x)

    • 2 years ago
  7. Calcmathlete Group Title
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    Or would it be xC2 = P(x)?

    • 2 years ago
  8. ganeshie8 Group Title
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    oh i see... but i guess forming 2 element groups involves just choosing elements, order doesnt matter...

    • 2 years ago
  9. Calcmathlete Group Title
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    Oh ok...then I get D for 16 and B for 17. I ddin't realize that, I was still thinking about the other part of the problem.

    • 2 years ago
  10. hartnn Group Title
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    if order doe not matter,then AB and BA are same,then use xC2

    • 2 years ago
  11. Calcmathlete Group Title
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    Ok, then it would be: 16. D 17. B ?

    • 2 years ago
  12. ganeshie8 Group Title
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    yeah i guess that it.... .

    • 2 years ago
  13. Calcmathlete Group Title
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    Alright. Thanks :)

    • 2 years ago
  14. ganeshie8 Group Title
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    np... :)

    • 2 years ago
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spraguer (Moderator)
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