## Calcmathlete 3 years ago Very confused on these particular problems...no clue what it's talking about...

1. Calcmathlete

2. Calcmathlete

@ganeshie8 I figured out C(x), but I don't get P(x)

3. ganeshie8

For 16th question, i think P(X) = 4C2

4. hartnn

the two element group...say there are 4 elements,ABCD,there will be 16 2 element grp,AA,AB,AC,....DD....but if repetition like AA are not allowed,then there will be 12...and if AB and BA are considered same ,then there will be 6....

5. Calcmathlete

I am getting B for the first one.

6. Calcmathlete

Because I did xP2 = P(x) and (n - 1)! = C(x)

7. Calcmathlete

Or would it be xC2 = P(x)?

8. ganeshie8

oh i see... but i guess forming 2 element groups involves just choosing elements, order doesnt matter...

9. Calcmathlete

Oh ok...then I get D for 16 and B for 17. I ddin't realize that, I was still thinking about the other part of the problem.

10. hartnn

if order doe not matter,then AB and BA are same,then use xC2

11. Calcmathlete

Ok, then it would be: 16. D 17. B ?

12. ganeshie8

yeah i guess that it.... .

13. Calcmathlete

Alright. Thanks :)

14. ganeshie8

np... :)