anonymous
  • anonymous
Very confused on these particular problems...no clue what it's talking about...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
anonymous
  • anonymous
@ganeshie8 I figured out C(x), but I don't get P(x)
ganeshie8
  • ganeshie8
For 16th question, i think P(X) = 4C2

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hartnn
  • hartnn
the two element group...say there are 4 elements,ABCD,there will be 16 2 element grp,AA,AB,AC,....DD....but if repetition like AA are not allowed,then there will be 12...and if AB and BA are considered same ,then there will be 6....
anonymous
  • anonymous
I am getting B for the first one.
anonymous
  • anonymous
Because I did xP2 = P(x) and (n - 1)! = C(x)
anonymous
  • anonymous
Or would it be xC2 = P(x)?
ganeshie8
  • ganeshie8
oh i see... but i guess forming 2 element groups involves just choosing elements, order doesnt matter...
anonymous
  • anonymous
Oh ok...then I get D for 16 and B for 17. I ddin't realize that, I was still thinking about the other part of the problem.
hartnn
  • hartnn
if order doe not matter,then AB and BA are same,then use xC2
anonymous
  • anonymous
Ok, then it would be: 16. D 17. B ?
ganeshie8
  • ganeshie8
yeah i guess that it.... .
anonymous
  • anonymous
Alright. Thanks :)
ganeshie8
  • ganeshie8
np... :)

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