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Calcmathlete
 3 years ago
Very confused on these particular problems...no clue what it's talking about...
Calcmathlete
 3 years ago
Very confused on these particular problems...no clue what it's talking about...

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Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0@ganeshie8 I figured out C(x), but I don't get P(x)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1For 16th question, i think P(X) = 4C2

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1the two element group...say there are 4 elements,ABCD,there will be 16 2 element grp,AA,AB,AC,....DD....but if repetition like AA are not allowed,then there will be 12...and if AB and BA are considered same ,then there will be 6....

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0I am getting B for the first one.

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0Because I did xP2 = P(x) and (n  1)! = C(x)

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0Or would it be xC2 = P(x)?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1oh i see... but i guess forming 2 element groups involves just choosing elements, order doesnt matter...

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0Oh ok...then I get D for 16 and B for 17. I ddin't realize that, I was still thinking about the other part of the problem.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1if order doe not matter,then AB and BA are same,then use xC2

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0Ok, then it would be: 16. D 17. B ?

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1yeah i guess that it.... .

Calcmathlete
 3 years ago
Best ResponseYou've already chosen the best response.0Alright. Thanks :)
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