jrosesweet
One solution of the equation 6x^2-19x+3=0 is 1/6
What is the other solution?
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RyanL.
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You can try doing the quadratic formula.
lgbasallote
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if 1/6 is a solution that means
x = 1/6 is a root
that means 6x - 1 is a factor
so just divide 6x^2 - 19x + 3 by 6x - 1
jrosesweet
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How do I do that?
lgbasallote
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long division? synthetic division? isnt that your lesosn?
sami-21
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sum of the roots of Quadratic equation
ax^2+bx+c=0 is
-b/a
so in our case
a=6
b=-19
so the sum of roots should be ,let unknown root is r
1/6+r=-(-19)/6
\[\Large r+\frac{1}{6}=\frac{19}{6}\]
OR
\[\Large r=\frac{19}{6}-\frac{1}{6}\]
simplify it and you got your answer !!
lgbasallote
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lol
sami-21
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yeah !!!!
lgbasallote
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wonder why wolfram disagrees though
sami-21
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let me check my Algebra then .
lgbasallote
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lol jk
Calcmathlete
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It is \[Sum = -\frac ba = \frac{19}{6}\]
Calcmathlete
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So, you suntract 1/6 to get 18/6 which simplifies...
sami-21
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lol i was right !!!!!!!
Calcmathlete
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Yup XD Just always remember the sign rule for these types of things ;)
sami-21
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@lgbasallote wolfram agrees with me :P
lgbasallote
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didnt you see the lol jk? lol
sami-21
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oops!!! now i saw lol jk :P
jrosesweet
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Sorry guys my computer froze!!
jrosesweet
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So the other solution is 18/6 ?!?
sami-21
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yes 18/6=3
jrosesweet
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Well spankyou. Spankyou all very much.