## jrosesweet 3 years ago One solution of the equation 6x^2-19x+3=0 is 1/6 What is the other solution?

1. RyanL.

You can try doing the quadratic formula.

2. lgbasallote

if 1/6 is a solution that means x = 1/6 is a root that means 6x - 1 is a factor so just divide 6x^2 - 19x + 3 by 6x - 1

3. jrosesweet

How do I do that?

4. lgbasallote

long division? synthetic division? isnt that your lesosn?

5. sami-21

sum of the roots of Quadratic equation ax^2+bx+c=0 is -b/a so in our case a=6 b=-19 so the sum of roots should be ,let unknown root is r 1/6+r=-(-19)/6 $\Large r+\frac{1}{6}=\frac{19}{6}$ OR $\Large r=\frac{19}{6}-\frac{1}{6}$ simplify it and you got your answer !!

6. lgbasallote

lol

7. sami-21

yeah !!!!

8. lgbasallote

wonder why wolfram disagrees though

9. sami-21

let me check my Algebra then .

10. lgbasallote

lol jk

11. Calcmathlete

It is $Sum = -\frac ba = \frac{19}{6}$

12. Calcmathlete

So, you suntract 1/6 to get 18/6 which simplifies...

13. sami-21

lol i was right !!!!!!!

14. Calcmathlete

Yup XD Just always remember the sign rule for these types of things ;)

15. sami-21

@lgbasallote wolfram agrees with me :P

16. lgbasallote

didnt you see the lol jk? lol

17. sami-21

oops!!! now i saw lol jk :P

18. jrosesweet

Sorry guys my computer froze!!

19. jrosesweet

So the other solution is 18/6 ?!?

20. sami-21

yes 18/6=3

21. jrosesweet

Well spankyou. Spankyou all very much.