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One solution of the equation 6x^2-19x+3=0 is 1/6 What is the other solution?

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You can try doing the quadratic formula.
if 1/6 is a solution that means x = 1/6 is a root that means 6x - 1 is a factor so just divide 6x^2 - 19x + 3 by 6x - 1
How do I do that?

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Other answers:

long division? synthetic division? isnt that your lesosn?
sum of the roots of Quadratic equation ax^2+bx+c=0 is -b/a so in our case a=6 b=-19 so the sum of roots should be ,let unknown root is r 1/6+r=-(-19)/6 \[\Large r+\frac{1}{6}=\frac{19}{6}\] OR \[\Large r=\frac{19}{6}-\frac{1}{6}\] simplify it and you got your answer !!
yeah !!!!
wonder why wolfram disagrees though
let me check my Algebra then .
lol jk
It is \[Sum = -\frac ba = \frac{19}{6}\]
So, you suntract 1/6 to get 18/6 which simplifies...
lol i was right !!!!!!!
Yup XD Just always remember the sign rule for these types of things ;)
@lgbasallote wolfram agrees with me :P
didnt you see the lol jk? lol
oops!!! now i saw lol jk :P
Sorry guys my computer froze!!
So the other solution is 18/6 ?!?
yes 18/6=3
Well spankyou. Spankyou all very much.

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