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jrosesweet

One solution of the equation 6x^2-19x+3=0 is 1/6 What is the other solution?

  • one year ago
  • one year ago

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  1. RyanL.
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    You can try doing the quadratic formula.

    • one year ago
  2. lgbasallote
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    if 1/6 is a solution that means x = 1/6 is a root that means 6x - 1 is a factor so just divide 6x^2 - 19x + 3 by 6x - 1

    • one year ago
  3. jrosesweet
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    How do I do that?

    • one year ago
  4. lgbasallote
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    long division? synthetic division? isnt that your lesosn?

    • one year ago
  5. sami-21
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    sum of the roots of Quadratic equation ax^2+bx+c=0 is -b/a so in our case a=6 b=-19 so the sum of roots should be ,let unknown root is r 1/6+r=-(-19)/6 \[\Large r+\frac{1}{6}=\frac{19}{6}\] OR \[\Large r=\frac{19}{6}-\frac{1}{6}\] simplify it and you got your answer !!

    • one year ago
  6. lgbasallote
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    lol

    • one year ago
  7. sami-21
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    yeah !!!!

    • one year ago
  8. lgbasallote
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    wonder why wolfram disagrees though

    • one year ago
  9. sami-21
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    let me check my Algebra then .

    • one year ago
  10. lgbasallote
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    lol jk

    • one year ago
  11. Calcmathlete
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    It is \[Sum = -\frac ba = \frac{19}{6}\]

    • one year ago
  12. Calcmathlete
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    So, you suntract 1/6 to get 18/6 which simplifies...

    • one year ago
  13. sami-21
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    lol i was right !!!!!!!

    • one year ago
  14. Calcmathlete
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    Yup XD Just always remember the sign rule for these types of things ;)

    • one year ago
  15. sami-21
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    @lgbasallote wolfram agrees with me :P

    • one year ago
  16. lgbasallote
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    didnt you see the lol jk? lol

    • one year ago
  17. sami-21
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    oops!!! now i saw lol jk :P

    • one year ago
  18. jrosesweet
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    Sorry guys my computer froze!!

    • one year ago
  19. jrosesweet
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    So the other solution is 18/6 ?!?

    • one year ago
  20. sami-21
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    yes 18/6=3

    • one year ago
  21. jrosesweet
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    Well spankyou. Spankyou all very much.

    • one year ago
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