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well..let's do the first first, alright?
okay please explain how to get answer i have no idea where to start on any of them ")
\[ x- 3 > -9\] do you know how to do it when its \((x-3) = -9\)
well i would make the x into -3
you are solving for \(x\)
is that what we have to ??
yes.. why not read this first to gain a better understanding.. http://www.sosmath.com/algebra/inequalities/ineq01/ineq01.html
okay i read it
if you have any problems then ask me..
okay for the first one what do we do??
\[x-3 >-9\] we are solving for \(x\) why not you try it first?
okay-3 is the answer because -3 times -3 is 9 and 9 is greater than -9 right
what? \(x\) is variabe..not times..
i thought were suppose to replace x with number??
looks like you have to solve for \(x\) not substituting..
ohhh k so we add 3 to both sides right?
@SchoolFreak , mini isn't already helping you!
@Mimi_x3 so then if we add 3 both sides we have x > -6
thats the answer?
you are basically solving for \(x\) thats all
oh haha x is greater than -6 , the graph would have open circle on -6 shading to the right is that right to?
okay lets try the next one
–2x + 1 ≤ –11
why dont you try and tell me what you get
okay i think the first step is to add 2 to both sides?
think first; why add to 2? since its +1?
just isolate the -2x in the first hand so you wont get confused
okay so then you add 1 to both sides?
@Mimi_x3 would substract 1 from both sides right?
yes you subtract because it was a positive in the rhs
–2x + 1 ≤ –11 Okay so now we have -2x ≤ 12
not quite.. whats -11 - 1?
yes, now you know what to do next
-2x ≤ -12 now we divide both sides by -2 and we have x ≥ 6
woo hooo also x is greater than or equal to 6 the graph would have a closed circle on 6 shading to the right
okay let me try this next one all by myself
10 < –3x + 1
alright, if you need help ask me :)
-9 > x @Mimi_x3 is that the answer??
nope..show me what you did
10 < -3x + 1 9 < -3x -9 > x
you made a small mistake whats 9/-3?
nope 9/ - 3
like 9 divide by negative 3
-3 is the answer??
yes but dont forget the inequality signs
-3 > x Is that the answer @Mimi_x3
not quite..the sign is wrong
No because we divide by a negative so we flip the sign
10 < -3x + 1 9< -3x -3x > 9
understand so far?
why did u turn the equation on the last part
i dont know how to explain..but for inequalities to have to change the sign when you swap the equation.. you dont need to turn it; i just turned to prevent confusion
you have to change*
oh i didnt know that
lets not turn the equation then lets start from 9< -3x
okay then then we dived and we -3 > x
then you still have to change the x for it to be in the front so x> -3
i mean x<-3
@Mimi_x3 2(x + 5) > 8x – 8 this is the next one it looks hard lol
not really..expand it
the first side first
if we do the first side we will have 2x + 10 right on the left side??
yeah. i gotta go now. sorry.
hopefully someone else can help you..if not i'll be back later :)