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SchoolFreak

INEQUAILTY !!!!

  • one year ago
  • one year ago

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  1. SchoolFreak
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    Please explain how to get it

    • one year ago
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  2. Mimi_x3
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    well..let's do the first first, alright?

    • one year ago
  3. Mimi_x3
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    first one*

    • one year ago
  4. SchoolFreak
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    okay please explain how to get answer i have no idea where to start on any of them ")

    • one year ago
  5. Mimi_x3
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    \[ x- 3 > -9\] do you know how to do it when its \((x-3) = -9\)

    • one year ago
  6. SchoolFreak
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    well i would make the x into -3

    • one year ago
  7. Mimi_x3
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    you are solving for \(x\)

    • one year ago
  8. SchoolFreak
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    is that what we have to ??

    • one year ago
  9. Mimi_x3
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    yes.. why not read this first to gain a better understanding.. http://www.sosmath.com/algebra/inequalities/ineq01/ineq01.html

    • one year ago
  10. SchoolFreak
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    okay i read it

    • one year ago
  11. Mimi_x3
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    if you have any problems then ask me..

    • one year ago
  12. SchoolFreak
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    okay for the first one what do we do??

    • one year ago
  13. Mimi_x3
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    \[x-3 >-9\] we are solving for \(x\) why not you try it first?

    • one year ago
  14. SchoolFreak
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    okay-3 is the answer because -3 times -3 is 9 and 9 is greater than -9 right

    • one year ago
  15. SchoolFreak
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    @Mimi_x3

    • one year ago
  16. Mimi_x3
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    what? \(x\) is variabe..not times..

    • one year ago
  17. Mimi_x3
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    a variable*

    • one year ago
  18. SchoolFreak
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    i thought were suppose to replace x with number??

    • one year ago
  19. Mimi_x3
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    looks like you have to solve for \(x\) not substituting..

    • one year ago
  20. SchoolFreak
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    ohhh k so we add 3 to both sides right?

    • one year ago
  21. saifoo.khan
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    @SchoolFreak , mini isn't already helping you!

    • one year ago
  22. saifoo.khan
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    is*

    • one year ago
  23. SchoolFreak
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    i know

    • one year ago
  24. SchoolFreak
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    @Mimi_x3 so then if we add 3 both sides we have x > -6

    • one year ago
  25. Mimi_x3
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    Yes!

    • one year ago
  26. SchoolFreak
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    thats the answer?

    • one year ago
  27. Mimi_x3
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    yeah lol

    • one year ago
  28. Mimi_x3
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    you are basically solving for \(x\) thats all

    • one year ago
  29. SchoolFreak
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    oh haha x is greater than -6 , the graph would have open circle on -6 shading to the right is that right to?

    • one year ago
  30. Mimi_x3
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    correct

    • one year ago
  31. SchoolFreak
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    okay lets try the next one

    • one year ago
  32. SchoolFreak
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    –2x + 1 ≤ –11

    • one year ago
  33. Mimi_x3
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    why dont you try and tell me what you get

    • one year ago
  34. SchoolFreak
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    okay i think the first step is to add 2 to both sides?

    • one year ago
  35. Mimi_x3
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    think first; why add to 2? since its +1?

    • one year ago
  36. Mimi_x3
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    just isolate the -2x in the first hand so you wont get confused

    • one year ago
  37. SchoolFreak
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    okay so then you add 1 to both sides?

    • one year ago
  38. SchoolFreak
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    @Mimi_x3 would substract 1 from both sides right?

    • one year ago
  39. Mimi_x3
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    yes you subtract because it was a positive in the rhs

    • one year ago
  40. SchoolFreak
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    –2x + 1 ≤ –11 Okay so now we have -2x ≤ 12

    • one year ago
  41. Mimi_x3
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    not quite.. whats -11 - 1?

    • one year ago
  42. SchoolFreak
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    ohhh -12

    • one year ago
  43. Mimi_x3
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    yes, now you know what to do next

    • one year ago
  44. SchoolFreak
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    -2x ≤ -12 now we divide both sides by -2 and we have x ≥ 6

    • one year ago
  45. Mimi_x3
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    yes!

    • one year ago
  46. SchoolFreak
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    woo hooo also x is greater than or equal to 6 the graph would have a closed circle on 6 shading to the right

    • one year ago
  47. Mimi_x3
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    yes

    • one year ago
  48. SchoolFreak
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    okay let me try this next one all by myself

    • one year ago
  49. SchoolFreak
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    10 < –3x + 1

    • one year ago
  50. Mimi_x3
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    alright, if you need help ask me :)

    • one year ago
  51. SchoolFreak
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    kk

    • one year ago
  52. SchoolFreak
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    -9 > x @Mimi_x3 is that the answer??

    • one year ago
  53. Mimi_x3
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    nope..show me what you did

    • one year ago
  54. SchoolFreak
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    10 < -3x + 1 9 < -3x -9 > x

    • one year ago
  55. Mimi_x3
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    you made a small mistake whats 9/-3?

    • one year ago
  56. SchoolFreak
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    3

    • one year ago
  57. Mimi_x3
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    nope 9/ - 3

    • one year ago
  58. Mimi_x3
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    like 9 divide by negative 3

    • one year ago
  59. SchoolFreak
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    -3 is the answer??

    • one year ago
  60. Mimi_x3
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    yes but dont forget the inequality signs

    • one year ago
  61. SchoolFreak
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    -3 > x Is that the answer @Mimi_x3

    • one year ago
  62. Mimi_x3
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    not quite..the sign is wrong

    • one year ago
  63. SchoolFreak
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    No because we divide by a negative so we flip the sign

    • one year ago
  64. Mimi_x3
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    10 < -3x + 1 9< -3x -3x > 9

    • one year ago
  65. Mimi_x3
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    understand so far?

    • one year ago
  66. SchoolFreak
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    why did u turn the equation on the last part

    • one year ago
  67. Mimi_x3
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    i dont know how to explain..but for inequalities to have to change the sign when you swap the equation.. you dont need to turn it; i just turned to prevent confusion

    • one year ago
  68. Mimi_x3
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    you have to change*

    • one year ago
  69. SchoolFreak
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    oh i didnt know that

    • one year ago
  70. Mimi_x3
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    lets not turn the equation then lets start from 9< -3x

    • one year ago
  71. SchoolFreak
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    okay then then we dived and we -3 > x

    • one year ago
  72. Mimi_x3
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    then you still have to change the x for it to be in the front so x> -3

    • one year ago
  73. Mimi_x3
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    i mean x<-3

    • one year ago
  74. SchoolFreak
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    ohh k

    • one year ago
  75. SchoolFreak
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    @Mimi_x3 2(x + 5) > 8x – 8 this is the next one it looks hard lol

    • one year ago
  76. Mimi_x3
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    not really..expand it

    • one year ago
  77. Mimi_x3
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    the first side first

    • one year ago
  78. SchoolFreak
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    if we do the first side we will have 2x + 10 right on the left side??

    • one year ago
  79. Mimi_x3
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    yeah. i gotta go now. sorry.

    • one year ago
  80. SchoolFreak
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    noo :(

    • one year ago
  81. Mimi_x3
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    hopefully someone else can help you..if not i'll be back later :)

    • one year ago
  82. SchoolFreak
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    okay

    • one year ago
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