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SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
Please explain how to get it
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
well..let's do the first first, alright?
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay please explain how to get answer i have no idea where to start on any of them ")
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
\[ x 3 > 9\] do you know how to do it when its \((x3) = 9\)
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
well i would make the x into 3
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
you are solving for \(x\)
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
is that what we have to ??
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
yes.. why not read this first to gain a better understanding.. http://www.sosmath.com/algebra/inequalities/ineq01/ineq01.html
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay i read it
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
if you have any problems then ask me..
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay for the first one what do we do??
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
\[x3 >9\] we are solving for \(x\) why not you try it first?
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay3 is the answer because 3 times 3 is 9 and 9 is greater than 9 right
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
@Mimi_x3
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
what? \(x\) is variabe..not times..
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
a variable*
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
i thought were suppose to replace x with number??
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
looks like you have to solve for \(x\) not substituting..
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
ohhh k so we add 3 to both sides right?
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
@SchoolFreak , mini isn't already helping you!
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
@Mimi_x3 so then if we add 3 both sides we have x > 6
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
thats the answer?
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
you are basically solving for \(x\) thats all
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
oh haha x is greater than 6 , the graph would have open circle on 6 shading to the right is that right to?
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay lets try the next one
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
–2x + 1 ≤ –11
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
why dont you try and tell me what you get
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay i think the first step is to add 2 to both sides?
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
think first; why add to 2? since its +1?
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
just isolate the 2x in the first hand so you wont get confused
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay so then you add 1 to both sides?
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
@Mimi_x3 would substract 1 from both sides right?
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
yes you subtract because it was a positive in the rhs
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
–2x + 1 ≤ –11 Okay so now we have 2x ≤ 12
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
not quite.. whats 11  1?
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
ohhh 12
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
yes, now you know what to do next
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
2x ≤ 12 now we divide both sides by 2 and we have x ≥ 6
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
woo hooo also x is greater than or equal to 6 the graph would have a closed circle on 6 shading to the right
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay let me try this next one all by myself
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
10 < –3x + 1
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
alright, if you need help ask me :)
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
9 > x @Mimi_x3 is that the answer??
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
nope..show me what you did
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
10 < 3x + 1 9 < 3x 9 > x
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
you made a small mistake whats 9/3?
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
nope 9/  3
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
like 9 divide by negative 3
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
3 is the answer??
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
yes but dont forget the inequality signs
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
3 > x Is that the answer @Mimi_x3
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
not quite..the sign is wrong
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
No because we divide by a negative so we flip the sign
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
10 < 3x + 1 9< 3x 3x > 9
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
understand so far?
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
why did u turn the equation on the last part
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
i dont know how to explain..but for inequalities to have to change the sign when you swap the equation.. you dont need to turn it; i just turned to prevent confusion
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
you have to change*
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
oh i didnt know that
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
lets not turn the equation then lets start from 9< 3x
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay then then we dived and we 3 > x
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
then you still have to change the x for it to be in the front so x> 3
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
i mean x<3
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
@Mimi_x3 2(x + 5) > 8x – 8 this is the next one it looks hard lol
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
not really..expand it
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
the first side first
 2 years ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
if we do the first side we will have 2x + 10 right on the left side??
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
yeah. i gotta go now. sorry.
 2 years ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
hopefully someone else can help you..if not i'll be back later :)
 2 years ago
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