## SchoolFreak 3 years ago INEQUAILTY !!!!

1. SchoolFreak

Please explain how to get it

2. Mimi_x3

well..let's do the first first, alright?

3. Mimi_x3

first one*

4. SchoolFreak

okay please explain how to get answer i have no idea where to start on any of them ")

5. Mimi_x3

\[ x- 3 > -9\] do you know how to do it when its \((x-3) = -9\)

6. SchoolFreak

well i would make the x into -3

7. Mimi_x3

you are solving for \(x\)

8. SchoolFreak

is that what we have to ??

9. Mimi_x3

yes.. why not read this first to gain a better understanding.. http://www.sosmath.com/algebra/inequalities/ineq01/ineq01.html

10. SchoolFreak

11. Mimi_x3

if you have any problems then ask me..

12. SchoolFreak

okay for the first one what do we do??

13. Mimi_x3

\[x-3 >-9\] we are solving for \(x\) why not you try it first?

14. SchoolFreak

okay-3 is the answer because -3 times -3 is 9 and 9 is greater than -9 right

15. SchoolFreak

@Mimi_x3

16. Mimi_x3

what? \(x\) is variabe..not times..

17. Mimi_x3

a variable*

18. SchoolFreak

i thought were suppose to replace x with number??

19. Mimi_x3

looks like you have to solve for \(x\) not substituting..

20. SchoolFreak

ohhh k so we add 3 to both sides right?

21. saifoo.khan

@SchoolFreak , mini isn't already helping you!

22. saifoo.khan

is*

23. SchoolFreak

i know

24. SchoolFreak

@Mimi_x3 so then if we add 3 both sides we have x > -6

25. Mimi_x3

Yes!

26. SchoolFreak

27. Mimi_x3

yeah lol

28. Mimi_x3

you are basically solving for \(x\) thats all

29. SchoolFreak

oh haha x is greater than -6 , the graph would have open circle on -6 shading to the right is that right to?

30. Mimi_x3

correct

31. SchoolFreak

okay lets try the next one

32. SchoolFreak

–2x + 1 ≤ –11

33. Mimi_x3

why dont you try and tell me what you get

34. SchoolFreak

okay i think the first step is to add 2 to both sides?

35. Mimi_x3

think first; why add to 2? since its +1?

36. Mimi_x3

just isolate the -2x in the first hand so you wont get confused

37. SchoolFreak

okay so then you add 1 to both sides?

38. SchoolFreak

@Mimi_x3 would substract 1 from both sides right?

39. Mimi_x3

yes you subtract because it was a positive in the rhs

40. SchoolFreak

–2x + 1 ≤ –11 Okay so now we have -2x ≤ 12

41. Mimi_x3

not quite.. whats -11 - 1?

42. SchoolFreak

ohhh -12

43. Mimi_x3

yes, now you know what to do next

44. SchoolFreak

-2x ≤ -12 now we divide both sides by -2 and we have x ≥ 6

45. Mimi_x3

yes!

46. SchoolFreak

woo hooo also x is greater than or equal to 6 the graph would have a closed circle on 6 shading to the right

47. Mimi_x3

yes

48. SchoolFreak

okay let me try this next one all by myself

49. SchoolFreak

10 < –3x + 1

50. Mimi_x3

alright, if you need help ask me :)

51. SchoolFreak

kk

52. SchoolFreak

-9 > x @Mimi_x3 is that the answer??

53. Mimi_x3

nope..show me what you did

54. SchoolFreak

10 < -3x + 1 9 < -3x -9 > x

55. Mimi_x3

you made a small mistake whats 9/-3?

56. SchoolFreak

3

57. Mimi_x3

nope 9/ - 3

58. Mimi_x3

like 9 divide by negative 3

59. SchoolFreak

60. Mimi_x3

yes but dont forget the inequality signs

61. SchoolFreak

-3 > x Is that the answer @Mimi_x3

62. Mimi_x3

not quite..the sign is wrong

63. SchoolFreak

No because we divide by a negative so we flip the sign

64. Mimi_x3

10 < -3x + 1 9< -3x -3x > 9

65. Mimi_x3

understand so far?

66. SchoolFreak

why did u turn the equation on the last part

67. Mimi_x3

i dont know how to explain..but for inequalities to have to change the sign when you swap the equation.. you dont need to turn it; i just turned to prevent confusion

68. Mimi_x3

you have to change*

69. SchoolFreak

oh i didnt know that

70. Mimi_x3

lets not turn the equation then lets start from 9< -3x

71. SchoolFreak

okay then then we dived and we -3 > x

72. Mimi_x3

then you still have to change the x for it to be in the front so x> -3

73. Mimi_x3

i mean x<-3

74. SchoolFreak

ohh k

75. SchoolFreak

@Mimi_x3 2(x + 5) > 8x – 8 this is the next one it looks hard lol

76. Mimi_x3

not really..expand it

77. Mimi_x3

the first side first

78. SchoolFreak

if we do the first side we will have 2x + 10 right on the left side??

79. Mimi_x3

yeah. i gotta go now. sorry.

80. SchoolFreak

noo :(

81. Mimi_x3

hopefully someone else can help you..if not i'll be back later :)

82. SchoolFreak

okay