anonymous
  • anonymous
INEQUAILTY !!!!
Mathematics
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anonymous
  • anonymous
INEQUAILTY !!!!
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Please explain how to get it
1 Attachment
Mimi_x3
  • Mimi_x3
well..let's do the first first, alright?
Mimi_x3
  • Mimi_x3
first one*

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anonymous
  • anonymous
okay please explain how to get answer i have no idea where to start on any of them ")
Mimi_x3
  • Mimi_x3
\[ x- 3 > -9\] do you know how to do it when its \((x-3) = -9\)
anonymous
  • anonymous
well i would make the x into -3
Mimi_x3
  • Mimi_x3
you are solving for \(x\)
anonymous
  • anonymous
is that what we have to ??
Mimi_x3
  • Mimi_x3
yes.. why not read this first to gain a better understanding.. http://www.sosmath.com/algebra/inequalities/ineq01/ineq01.html
anonymous
  • anonymous
okay i read it
Mimi_x3
  • Mimi_x3
if you have any problems then ask me..
anonymous
  • anonymous
okay for the first one what do we do??
Mimi_x3
  • Mimi_x3
\[x-3 >-9\] we are solving for \(x\) why not you try it first?
anonymous
  • anonymous
okay-3 is the answer because -3 times -3 is 9 and 9 is greater than -9 right
anonymous
  • anonymous
Mimi_x3
  • Mimi_x3
what? \(x\) is variabe..not times..
Mimi_x3
  • Mimi_x3
a variable*
anonymous
  • anonymous
i thought were suppose to replace x with number??
Mimi_x3
  • Mimi_x3
looks like you have to solve for \(x\) not substituting..
anonymous
  • anonymous
ohhh k so we add 3 to both sides right?
saifoo.khan
  • saifoo.khan
@SchoolFreak , mini isn't already helping you!
saifoo.khan
  • saifoo.khan
is*
anonymous
  • anonymous
i know
anonymous
  • anonymous
@Mimi_x3 so then if we add 3 both sides we have x > -6
Mimi_x3
  • Mimi_x3
Yes!
anonymous
  • anonymous
thats the answer?
Mimi_x3
  • Mimi_x3
yeah lol
Mimi_x3
  • Mimi_x3
you are basically solving for \(x\) thats all
anonymous
  • anonymous
oh haha x is greater than -6 , the graph would have open circle on -6 shading to the right is that right to?
Mimi_x3
  • Mimi_x3
correct
anonymous
  • anonymous
okay lets try the next one
anonymous
  • anonymous
–2x + 1 ≤ –11
Mimi_x3
  • Mimi_x3
why dont you try and tell me what you get
anonymous
  • anonymous
okay i think the first step is to add 2 to both sides?
Mimi_x3
  • Mimi_x3
think first; why add to 2? since its +1?
Mimi_x3
  • Mimi_x3
just isolate the -2x in the first hand so you wont get confused
anonymous
  • anonymous
okay so then you add 1 to both sides?
anonymous
  • anonymous
@Mimi_x3 would substract 1 from both sides right?
Mimi_x3
  • Mimi_x3
yes you subtract because it was a positive in the rhs
anonymous
  • anonymous
–2x + 1 ≤ –11 Okay so now we have -2x ≤ 12
Mimi_x3
  • Mimi_x3
not quite.. whats -11 - 1?
anonymous
  • anonymous
ohhh -12
Mimi_x3
  • Mimi_x3
yes, now you know what to do next
anonymous
  • anonymous
-2x ≤ -12 now we divide both sides by -2 and we have x ≥ 6
Mimi_x3
  • Mimi_x3
yes!
anonymous
  • anonymous
woo hooo also x is greater than or equal to 6 the graph would have a closed circle on 6 shading to the right
Mimi_x3
  • Mimi_x3
yes
anonymous
  • anonymous
okay let me try this next one all by myself
anonymous
  • anonymous
10 < –3x + 1
Mimi_x3
  • Mimi_x3
alright, if you need help ask me :)
anonymous
  • anonymous
kk
anonymous
  • anonymous
-9 > x @Mimi_x3 is that the answer??
Mimi_x3
  • Mimi_x3
nope..show me what you did
anonymous
  • anonymous
10 < -3x + 1 9 < -3x -9 > x
Mimi_x3
  • Mimi_x3
you made a small mistake whats 9/-3?
anonymous
  • anonymous
3
Mimi_x3
  • Mimi_x3
nope 9/ - 3
Mimi_x3
  • Mimi_x3
like 9 divide by negative 3
anonymous
  • anonymous
-3 is the answer??
Mimi_x3
  • Mimi_x3
yes but dont forget the inequality signs
anonymous
  • anonymous
-3 > x Is that the answer @Mimi_x3
Mimi_x3
  • Mimi_x3
not quite..the sign is wrong
anonymous
  • anonymous
No because we divide by a negative so we flip the sign
Mimi_x3
  • Mimi_x3
10 < -3x + 1 9< -3x -3x > 9
Mimi_x3
  • Mimi_x3
understand so far?
anonymous
  • anonymous
why did u turn the equation on the last part
Mimi_x3
  • Mimi_x3
i dont know how to explain..but for inequalities to have to change the sign when you swap the equation.. you dont need to turn it; i just turned to prevent confusion
Mimi_x3
  • Mimi_x3
you have to change*
anonymous
  • anonymous
oh i didnt know that
Mimi_x3
  • Mimi_x3
lets not turn the equation then lets start from 9< -3x
anonymous
  • anonymous
okay then then we dived and we -3 > x
Mimi_x3
  • Mimi_x3
then you still have to change the x for it to be in the front so x> -3
Mimi_x3
  • Mimi_x3
i mean x<-3
anonymous
  • anonymous
ohh k
anonymous
  • anonymous
@Mimi_x3 2(x + 5) > 8x – 8 this is the next one it looks hard lol
Mimi_x3
  • Mimi_x3
not really..expand it
Mimi_x3
  • Mimi_x3
the first side first
anonymous
  • anonymous
if we do the first side we will have 2x + 10 right on the left side??
Mimi_x3
  • Mimi_x3
yeah. i gotta go now. sorry.
anonymous
  • anonymous
noo :(
Mimi_x3
  • Mimi_x3
hopefully someone else can help you..if not i'll be back later :)
anonymous
  • anonymous
okay

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