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SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
Please explain how to get it
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
well..let's do the first first, alright?
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
first one*
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay please explain how to get answer i have no idea where to start on any of them ")
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
\[ x 3 > 9\] do you know how to do it when its \((x3) = 9\)
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
well i would make the x into 3
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
you are solving for \(x\)
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
is that what we have to ??
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
yes.. why not read this first to gain a better understanding.. http://www.sosmath.com/algebra/inequalities/ineq01/ineq01.html
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay i read it
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
if you have any problems then ask me..
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay for the first one what do we do??
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
\[x3 >9\] we are solving for \(x\) why not you try it first?
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay3 is the answer because 3 times 3 is 9 and 9 is greater than 9 right
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
@Mimi_x3
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
what? \(x\) is variabe..not times..
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
a variable*
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
i thought were suppose to replace x with number??
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
looks like you have to solve for \(x\) not substituting..
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
ohhh k so we add 3 to both sides right?
 one year ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.1
@SchoolFreak , mini isn't already helping you!
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
i know
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
@Mimi_x3 so then if we add 3 both sides we have x > 6
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
thats the answer?
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
you are basically solving for \(x\) thats all
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
oh haha x is greater than 6 , the graph would have open circle on 6 shading to the right is that right to?
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay lets try the next one
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
–2x + 1 ≤ –11
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
why dont you try and tell me what you get
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay i think the first step is to add 2 to both sides?
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
think first; why add to 2? since its +1?
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
just isolate the 2x in the first hand so you wont get confused
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay so then you add 1 to both sides?
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
@Mimi_x3 would substract 1 from both sides right?
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
yes you subtract because it was a positive in the rhs
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
–2x + 1 ≤ –11 Okay so now we have 2x ≤ 12
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
not quite.. whats 11  1?
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
ohhh 12
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
yes, now you know what to do next
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
2x ≤ 12 now we divide both sides by 2 and we have x ≥ 6
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
woo hooo also x is greater than or equal to 6 the graph would have a closed circle on 6 shading to the right
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay let me try this next one all by myself
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
10 < –3x + 1
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
alright, if you need help ask me :)
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
9 > x @Mimi_x3 is that the answer??
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
nope..show me what you did
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
10 < 3x + 1 9 < 3x 9 > x
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
you made a small mistake whats 9/3?
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
nope 9/  3
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
like 9 divide by negative 3
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
3 is the answer??
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
yes but dont forget the inequality signs
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
3 > x Is that the answer @Mimi_x3
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
not quite..the sign is wrong
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
No because we divide by a negative so we flip the sign
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
10 < 3x + 1 9< 3x 3x > 9
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
understand so far?
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
why did u turn the equation on the last part
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
i dont know how to explain..but for inequalities to have to change the sign when you swap the equation.. you dont need to turn it; i just turned to prevent confusion
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
you have to change*
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
oh i didnt know that
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
lets not turn the equation then lets start from 9< 3x
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
okay then then we dived and we 3 > x
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
then you still have to change the x for it to be in the front so x> 3
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
i mean x<3
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
@Mimi_x3 2(x + 5) > 8x – 8 this is the next one it looks hard lol
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
not really..expand it
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
the first side first
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
if we do the first side we will have 2x + 10 right on the left side??
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
yeah. i gotta go now. sorry.
 one year ago

SchoolFreak Group TitleBest ResponseYou've already chosen the best response.0
noo :(
 one year ago

Mimi_x3 Group TitleBest ResponseYou've already chosen the best response.1
hopefully someone else can help you..if not i'll be back later :)
 one year ago
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