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anonymous
 3 years ago
INEQUAILTY !!!!
anonymous
 3 years ago
INEQUAILTY !!!!

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Please explain how to get it

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1well..let's do the first first, alright?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay please explain how to get answer i have no idea where to start on any of them ")

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1\[ x 3 > 9\] do you know how to do it when its \((x3) = 9\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well i would make the x into 3

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1you are solving for \(x\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is that what we have to ??

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1yes.. why not read this first to gain a better understanding.. http://www.sosmath.com/algebra/inequalities/ineq01/ineq01.html

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1if you have any problems then ask me..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay for the first one what do we do??

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1\[x3 >9\] we are solving for \(x\) why not you try it first?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay3 is the answer because 3 times 3 is 9 and 9 is greater than 9 right

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1what? \(x\) is variabe..not times..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i thought were suppose to replace x with number??

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1looks like you have to solve for \(x\) not substituting..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohhh k so we add 3 to both sides right?

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.1@SchoolFreak , mini isn't already helping you!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Mimi_x3 so then if we add 3 both sides we have x > 6

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1you are basically solving for \(x\) thats all

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh haha x is greater than 6 , the graph would have open circle on 6 shading to the right is that right to?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay lets try the next one

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1why dont you try and tell me what you get

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay i think the first step is to add 2 to both sides?

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1think first; why add to 2? since its +1?

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1just isolate the 2x in the first hand so you wont get confused

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay so then you add 1 to both sides?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Mimi_x3 would substract 1 from both sides right?

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1yes you subtract because it was a positive in the rhs

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0–2x + 1 ≤ –11 Okay so now we have 2x ≤ 12

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1not quite.. whats 11  1?

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1yes, now you know what to do next

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.02x ≤ 12 now we divide both sides by 2 and we have x ≥ 6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0woo hooo also x is greater than or equal to 6 the graph would have a closed circle on 6 shading to the right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay let me try this next one all by myself

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1alright, if you need help ask me :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.09 > x @Mimi_x3 is that the answer??

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1nope..show me what you did

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.010 < 3x + 1 9 < 3x 9 > x

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1you made a small mistake whats 9/3?

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1like 9 divide by negative 3

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1yes but dont forget the inequality signs

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.03 > x Is that the answer @Mimi_x3

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1not quite..the sign is wrong

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No because we divide by a negative so we flip the sign

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.110 < 3x + 1 9< 3x 3x > 9

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0why did u turn the equation on the last part

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1i dont know how to explain..but for inequalities to have to change the sign when you swap the equation.. you dont need to turn it; i just turned to prevent confusion

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1lets not turn the equation then lets start from 9< 3x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay then then we dived and we 3 > x

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1then you still have to change the x for it to be in the front so x> 3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Mimi_x3 2(x + 5) > 8x – 8 this is the next one it looks hard lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if we do the first side we will have 2x + 10 right on the left side??

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1yeah. i gotta go now. sorry.

Mimi_x3
 3 years ago
Best ResponseYou've already chosen the best response.1hopefully someone else can help you..if not i'll be back later :)
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