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saifoo.khan
 3 years ago
The length of a diagonal of a square is "j+3" . Find the area of square.
saifoo.khan
 3 years ago
The length of a diagonal of a square is "j+3" . Find the area of square.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1344679641263:dw

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.0Ah, great! @Akpellet_math

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[(j ^{2}+6j+9) / 2\]

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.0I was half way already! :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its Akpellet not AKPELLET

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[x^2 + x^2 = (j+3)^2 \implies 2x^2 = 1 + 9 + 6j \implies x^2 = 4 + 3j\] \[x^2 = Area\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but @waterineyesthere 1 will be j^2 as we have 2 xpand (j+3)^2.........using algebraic identity

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think I have taken 1..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[(j+3)^2 = j^2 + 9 + 6j \implies 1 + 9 + 6j \implies 8 + 6j\]
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