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saifoo.khan

  • 3 years ago

The length of a diagonal of a square is "j+3" . Find the area of square.

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  1. Akshit_math
    • 3 years ago
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    |dw:1344679641263:dw|

  2. saifoo.khan
    • 3 years ago
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    Ah, great! @Akpellet_math

  3. Akshit_math
    • 3 years ago
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    \[(j ^{2}+6j+9) / 2\]

  4. saifoo.khan
    • 3 years ago
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    I was half way already! :D

  5. waterineyes
    • 3 years ago
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    \[x^2 = 4 + 3j\]

  6. Akshit_math
    • 3 years ago
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    its Akpellet not AKPELLET

  7. saifoo.khan
    • 3 years ago
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    lol.

  8. waterineyes
    • 3 years ago
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    \[x^2 + x^2 = (j+3)^2 \implies 2x^2 = -1 + 9 + 6j \implies x^2 = 4 + 3j\] \[x^2 = Area\]

  9. Akshit_math
    • 3 years ago
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    but @waterineyesthere -1 will be j^2 as we have 2 xpand (j+3)^2.........using algebraic identity

  10. waterineyes
    • 3 years ago
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    I think I have taken -1..

  11. waterineyes
    • 3 years ago
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    \[(j+3)^2 = j^2 + 9 + 6j \implies -1 + 9 + 6j \implies 8 + 6j\]

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