saifoo.khan
The length of a diagonal of a square is "j+3" . Find the area of square.



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Akshit_math
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dw:1344679641263:dw

saifoo.khan
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Ah, great! @Akpellet_math

Akshit_math
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\[(j ^{2}+6j+9) / 2\]

saifoo.khan
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I was half way already! :D

waterineyes
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\[x^2 = 4 + 3j\]

Akshit_math
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its Akpellet not AKPELLET

saifoo.khan
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lol.

waterineyes
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\[x^2 + x^2 = (j+3)^2 \implies 2x^2 = 1 + 9 + 6j \implies x^2 = 4 + 3j\]
\[x^2 = Area\]

Akshit_math
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but @waterineyesthere 1 will be j^2 as we have 2 xpand (j+3)^2.........using algebraic identity

waterineyes
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I think I have taken 1..

waterineyes
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\[(j+3)^2 = j^2 + 9 + 6j \implies 1 + 9 + 6j \implies 8 + 6j\]