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The length of a diagonal of a square is "j+3" . Find the area of square.
 one year ago
 one year ago
The length of a diagonal of a square is "j+3" . Find the area of square.
 one year ago
 one year ago

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Akshit_mathBest ResponseYou've already chosen the best response.1
dw:1344679641263:dw
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.0
Ah, great! @Akpellet_math
 one year ago

Akshit_mathBest ResponseYou've already chosen the best response.1
\[(j ^{2}+6j+9) / 2\]
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.0
I was half way already! :D
 one year ago

Akshit_mathBest ResponseYou've already chosen the best response.1
its Akpellet not AKPELLET
 one year ago

waterineyesBest ResponseYou've already chosen the best response.0
\[x^2 + x^2 = (j+3)^2 \implies 2x^2 = 1 + 9 + 6j \implies x^2 = 4 + 3j\] \[x^2 = Area\]
 one year ago

Akshit_mathBest ResponseYou've already chosen the best response.1
but @waterineyesthere 1 will be j^2 as we have 2 xpand (j+3)^2.........using algebraic identity
 one year ago

waterineyesBest ResponseYou've already chosen the best response.0
I think I have taken 1..
 one year ago

waterineyesBest ResponseYou've already chosen the best response.0
\[(j+3)^2 = j^2 + 9 + 6j \implies 1 + 9 + 6j \implies 8 + 6j\]
 one year ago
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