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saifoo.khan Group Title

The sum of five integers is 190. If one of these numbers is removed, the average of the four remaining numbers is between 34.5 and 36, inclusive. What is one possible value for the number that was removed?

  • one year ago
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  1. kartiksriramk Group Title
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    Let the five numbers be a,b,c,d,e.And let e be the number that is removed. a+b+c+d+e = 190. \[34.5\le (190-e)/4 \le 36 \] On simplifying the above inequality,we get \[138 \le 190-e \le 144\] \[-52 \le -e \le -46\] \[46 \le e \le 52\] So, the value of the missing integer e can be between 46 and 52 inclusive.

    • one year ago
  2. kartiksriramk Group Title
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    I forgot to mention this: The average after removing e is (190-e)/4 .

    • one year ago
  3. saifoo.khan Group Title
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    Wow, thanks a ton! @kartiksriramk

    • one year ago
  4. kartiksriramk Group Title
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    You're welcome man. Nice question by the way.

    • one year ago
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