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saifoo.khan
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The sum of five integers is 190. If one of these numbers is removed, the average of the four remaining numbers is between 34.5 and 36, inclusive. What is one possible value for the number that was removed?
 2 years ago
 2 years ago
saifoo.khan Group Title
The sum of five integers is 190. If one of these numbers is removed, the average of the four remaining numbers is between 34.5 and 36, inclusive. What is one possible value for the number that was removed?
 2 years ago
 2 years ago

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kartiksriramk Group TitleBest ResponseYou've already chosen the best response.3
Let the five numbers be a,b,c,d,e.And let e be the number that is removed. a+b+c+d+e = 190. \[34.5\le (190e)/4 \le 36 \] On simplifying the above inequality,we get \[138 \le 190e \le 144\] \[52 \le e \le 46\] \[46 \le e \le 52\] So, the value of the missing integer e can be between 46 and 52 inclusive.
 2 years ago

kartiksriramk Group TitleBest ResponseYou've already chosen the best response.3
I forgot to mention this: The average after removing e is (190e)/4 .
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
Wow, thanks a ton! @kartiksriramk
 2 years ago

kartiksriramk Group TitleBest ResponseYou've already chosen the best response.3
You're welcome man. Nice question by the way.
 2 years ago
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