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saifoo.khan

  • 3 years ago

The sum of five integers is 190. If one of these numbers is removed, the average of the four remaining numbers is between 34.5 and 36, inclusive. What is one possible value for the number that was removed?

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  1. kartiksriramk
    • 3 years ago
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    Let the five numbers be a,b,c,d,e.And let e be the number that is removed. a+b+c+d+e = 190. \[34.5\le (190-e)/4 \le 36 \] On simplifying the above inequality,we get \[138 \le 190-e \le 144\] \[-52 \le -e \le -46\] \[46 \le e \le 52\] So, the value of the missing integer e can be between 46 and 52 inclusive.

  2. kartiksriramk
    • 3 years ago
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    I forgot to mention this: The average after removing e is (190-e)/4 .

  3. saifoo.khan
    • 3 years ago
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    Wow, thanks a ton! @kartiksriramk

  4. kartiksriramk
    • 3 years ago
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    You're welcome man. Nice question by the way.

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