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TuringTestBest ResponseYou've already chosen the best response.1
dw:1344703864992:dwthe back tire pushes trying to move clockwise, and static friction's reactive force pushes to the right the wheel in the from is being pushed by a force of friction to the left (due to the relative motion of the ground, as you said) which also causes the tire to move clockwise I misspoke to say that static the friction has no direction in this case, that's why I needed to draw it
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
wheel in the front*
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.1
so will the back tire continue to rotate clockwise even when friction pushes it to the right/forward??
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
we force the tire to move clockwise by turning the pedals. the force acting to the left is the reactive force of friction of the ground on the tire hence the friction on the back tire is a result of us *forcing* the tire to move clockwise, so yes the wheel will move that way
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
at the bottom of the tire we have a balance of forcesdw:1344704471674:dwthis is the force that the tire exerts on the ground due to our pedaling (human power) since there is not slippage of the back wheel this force must be balanced by friction\[\vec F=\vec f\]hence friction points forward, which causes the bike to move forward
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
dw:1344704602174:dw
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.1
ok thanks can u explain the friction and motion of a car also plz
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
it is identical, but with double tires and a motor instead of a human to power it
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.1
forward force on backward tires and vice versa??
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
in terms of friction yes unless it is fourwheel drive, then the force of friction acts forwards for all tires
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
...because there is a motor pushing the front tires as well in 4wheel drive make sense?
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.1
yeah i think so.... so all tires are pushed forward. what happens while braking??
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
the car slows down so what direction must friction be acting?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
careful in your wording of the situation btw in a 4wheel drive the four tires are pushing against the ground *opposite* the direction of the car's motion (backwards) however friction pushes opposite that, hence the car moves forward
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
dw:1344705424977:dw
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
...force of motor against the ground I mean
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.1
do all tires experience backward frictional force while braking? and while moving and breaking is the friction static or kinetic?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
I already explained that while moving the friction is static (that is why the forces sum to zero and friction acts forward) while breaking the car is skidding (slipping) and slowing down. any wheels that lock due to the breaks will be skidding against the ground is that static or kinetic? is it into or opposite the direction of motion?
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.1
ok so its kinetic while braking and opp to motion right?
 one year ago

shayanreloadedBest ResponseYou've already chosen the best response.1
thanks a lot :)
 one year ago
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