Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Qawi Group Title

sqrt 81/ sqrt 7

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. Qawi Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    options 9/7 9sqrt7/7 sqrt7/7 9/sqrt7

    • 2 years ago
  2. amistre64 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    sqrt are like blobs of jelly; they cen combine and separate at will

    • 2 years ago
  3. amistre64 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i recall alot of texts saying that sqrt in the bottom tho are not proper .... for some reason

    • 2 years ago
  4. RyanL. Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\frac{\sqrt {81}}{ \sqrt {7}} =\frac{\sqrt {9*9}}{ \sqrt {7}}\]

    • 2 years ago
  5. RyanL. Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    you think can simplify it from there?

    • 2 years ago
  6. amistre64 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    there are 2 equal options .....

    • 2 years ago
  7. RyanL. Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    no look again

    • 2 years ago
  8. Qawi Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    9 / sqrt 7

    • 2 years ago
  9. RyanL. Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    good job you are right\[\frac{9 }{ \sqrt {7}}\]

    • 2 years ago
  10. amistre64 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\frac{9\sqrt7}{7}=\frac{9}{\sqrt7}\] \[\frac{\sqrt7}{7}=\frac{1}{\sqrt7}\] \[\frac{\sqrt7\sqrt7}{7\sqrt7}=\frac{1}{\sqrt7}\] \[\frac{7}{7\sqrt7}=\frac{1}{\sqrt7}\] \[\frac{1}{\sqrt7}=\frac{1}{\sqrt7}\]

    • 2 years ago
  11. amistre64 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    so the issue is; which one is "proper" form

    • 2 years ago
  12. Qawi Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yess!!!! thank you so much

    • 2 years ago
  13. RyanL. Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    I think the issue is where the boundaries are since I can interpret in a completely different way if I try.

    • 2 years ago
  14. RyanL. Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    That's why I don't trust answer choices....

    • 2 years ago
  15. Qawi Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks anyway amistre

    • 2 years ago
  16. amistre64 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i read it right ... confused myself as a sipped the coffee

    • 2 years ago
  17. amistre64 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    http://www.purplemath.com/modules/radicals5.htm no radicals under

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.