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Qawi

  • 3 years ago

sqrt 81/ sqrt 7

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  1. Qawi
    • 3 years ago
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    options 9/7 9sqrt7/7 sqrt7/7 9/sqrt7

  2. amistre64
    • 3 years ago
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    sqrt are like blobs of jelly; they cen combine and separate at will

  3. amistre64
    • 3 years ago
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    i recall alot of texts saying that sqrt in the bottom tho are not proper .... for some reason

  4. RyanL.
    • 3 years ago
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    \[\frac{\sqrt {81}}{ \sqrt {7}} =\frac{\sqrt {9*9}}{ \sqrt {7}}\]

  5. RyanL.
    • 3 years ago
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    you think can simplify it from there?

  6. amistre64
    • 3 years ago
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    there are 2 equal options .....

  7. RyanL.
    • 3 years ago
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    no look again

  8. Qawi
    • 3 years ago
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    9 / sqrt 7

  9. RyanL.
    • 3 years ago
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    good job you are right\[\frac{9 }{ \sqrt {7}}\]

  10. amistre64
    • 3 years ago
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    \[\frac{9\sqrt7}{7}=\frac{9}{\sqrt7}\] \[\frac{\sqrt7}{7}=\frac{1}{\sqrt7}\] \[\frac{\sqrt7\sqrt7}{7\sqrt7}=\frac{1}{\sqrt7}\] \[\frac{7}{7\sqrt7}=\frac{1}{\sqrt7}\] \[\frac{1}{\sqrt7}=\frac{1}{\sqrt7}\]

  11. amistre64
    • 3 years ago
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    so the issue is; which one is "proper" form

  12. Qawi
    • 3 years ago
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    yess!!!! thank you so much

  13. RyanL.
    • 3 years ago
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    I think the issue is where the boundaries are since I can interpret in a completely different way if I try.

  14. RyanL.
    • 3 years ago
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    That's why I don't trust answer choices....

  15. Qawi
    • 3 years ago
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    thanks anyway amistre

  16. amistre64
    • 3 years ago
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    i read it right ... confused myself as a sipped the coffee

  17. amistre64
    • 3 years ago
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    http://www.purplemath.com/modules/radicals5.htm no radicals under

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