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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1i got my answer but apparently i was wrong this from @lopez_hatesmath

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1maybe some fresh eyes would help

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1nvm sorry to bother you

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1it was this \[a_1=\frac{3}{2}; a_{n+1}=\frac{n^2+1}{n}\times a_n\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1that is, the \(a_n\) was in the NUMERATOR

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1so now it is not so bad replace \(n=1\) on the right hand side to get \(a_2\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1you get \[a_2=\frac{1^2+1}{1}\times \frac{3}{2}\] \[a_2=2\times\frac{3}{2}\] \[a_2=3\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1now replace \(n\) by 2 on the right hand side to get \[a_3=\frac{2^2+1}{2}\times 3\] \[a_3=\frac{5}{2}\times 3\] \[a_3=\frac{15}{2}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1how are we doing so far?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1one more? \[a_4=\frac{3^2+1}{3}\times \frac{15}{2}\] \[a_4=\frac{10}{3}\times \frac{15}{2}\] \[a_4=25\]

lopez_hatesmath
 2 years ago
Best ResponseYou've already chosen the best response.0okayy i got it!

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1not so bad that is the idea, i thought the term was in the denominator which is why i was screwing it up

lopez_hatesmath
 2 years ago
Best ResponseYou've already chosen the best response.0gotcha thanks for the help man.

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1yw good luck with the next one, but it works the same so you should be good to go
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