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## satellite73 3 years ago find the first 4 terms $a_1=\frac{3}{2}; a_{n+1}=\frac{n^2+1}{n(a_n)}$

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1. anonymous

i got my answer but apparently i was wrong this from @lopez_hatesmath

2. anonymous

maybe some fresh eyes would help

3. anonymous

nvm sorry to bother you

4. anonymous

:(

5. anonymous

i got it

6. anonymous

swagg

7. anonymous

it was this $a_1=\frac{3}{2}; a_{n+1}=\frac{n^2+1}{n}\times a_n$

8. anonymous

that is, the $$a_n$$ was in the NUMERATOR

9. anonymous

so now it is not so bad replace $$n=1$$ on the right hand side to get $$a_2$$

10. anonymous

you get $a_2=\frac{1^2+1}{1}\times \frac{3}{2}$ $a_2=2\times\frac{3}{2}$ $a_2=3$

11. anonymous

now replace $$n$$ by 2 on the right hand side to get $a_3=\frac{2^2+1}{2}\times 3$ $a_3=\frac{5}{2}\times 3$ $a_3=\frac{15}{2}$

12. anonymous

how are we doing so far?

13. anonymous

good :)

14. anonymous

one more? $a_4=\frac{3^2+1}{3}\times \frac{15}{2}$ $a_4=\frac{10}{3}\times \frac{15}{2}$ $a_4=25$

15. anonymous

okayy i got it!

16. anonymous

not so bad that is the idea, i thought the term was in the denominator which is why i was screwing it up

17. anonymous

gotcha thanks for the help man.

18. anonymous

yw good luck with the next one, but it works the same so you should be good to go

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