satellite73
  • satellite73
find the first 4 terms \[a_1=\frac{3}{2}; a_{n+1}=\frac{n^2+1}{n(a_n)}\]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
i got my answer but apparently i was wrong this from @lopez_hatesmath
anonymous
  • anonymous
maybe some fresh eyes would help
anonymous
  • anonymous
nvm sorry to bother you

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anonymous
  • anonymous
:(
anonymous
  • anonymous
i got it
anonymous
  • anonymous
swagg
anonymous
  • anonymous
it was this \[a_1=\frac{3}{2}; a_{n+1}=\frac{n^2+1}{n}\times a_n\]
anonymous
  • anonymous
that is, the \(a_n\) was in the NUMERATOR
anonymous
  • anonymous
so now it is not so bad replace \(n=1\) on the right hand side to get \(a_2\)
anonymous
  • anonymous
you get \[a_2=\frac{1^2+1}{1}\times \frac{3}{2}\] \[a_2=2\times\frac{3}{2}\] \[a_2=3\]
anonymous
  • anonymous
now replace \(n\) by 2 on the right hand side to get \[a_3=\frac{2^2+1}{2}\times 3\] \[a_3=\frac{5}{2}\times 3\] \[a_3=\frac{15}{2}\]
anonymous
  • anonymous
how are we doing so far?
anonymous
  • anonymous
good :)
anonymous
  • anonymous
one more? \[a_4=\frac{3^2+1}{3}\times \frac{15}{2}\] \[a_4=\frac{10}{3}\times \frac{15}{2}\] \[a_4=25\]
anonymous
  • anonymous
okayy i got it!
anonymous
  • anonymous
not so bad that is the idea, i thought the term was in the denominator which is why i was screwing it up
anonymous
  • anonymous
gotcha thanks for the help man.
anonymous
  • anonymous
yw good luck with the next one, but it works the same so you should be good to go

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