satellite73
find the first 4 terms
\[a_1=\frac{3}{2}; a_{n+1}=\frac{n^2+1}{n(a_n)}\]



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anonymous
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i got my answer but apparently i was wrong
this from @lopez_hatesmath

anonymous
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maybe some fresh eyes would help

anonymous
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nvm sorry to bother you

lopez_hatesmath
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:(

anonymous
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i got it

lopez_hatesmath
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swagg

anonymous
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it was this
\[a_1=\frac{3}{2}; a_{n+1}=\frac{n^2+1}{n}\times a_n\]

anonymous
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that is, the \(a_n\) was in the NUMERATOR

anonymous
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so now it is not so bad
replace \(n=1\) on the right hand side to get \(a_2\)

anonymous
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you get
\[a_2=\frac{1^2+1}{1}\times \frac{3}{2}\]
\[a_2=2\times\frac{3}{2}\]
\[a_2=3\]

anonymous
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now replace \(n\) by 2 on the right hand side to get
\[a_3=\frac{2^2+1}{2}\times 3\]
\[a_3=\frac{5}{2}\times 3\]
\[a_3=\frac{15}{2}\]

anonymous
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how are we doing so far?

lopez_hatesmath
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good :)

anonymous
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one more?
\[a_4=\frac{3^2+1}{3}\times \frac{15}{2}\]
\[a_4=\frac{10}{3}\times \frac{15}{2}\]
\[a_4=25\]

lopez_hatesmath
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okayy i got it!

anonymous
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not so bad
that is the idea, i thought the term was in the denominator which is why i was screwing it up

lopez_hatesmath
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gotcha thanks for the help man.

anonymous
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yw
good luck with the next one, but it works the same so you should be good to go