## satellite73 3 years ago find the first 4 terms $a_1=\frac{3}{2}; a_{n+1}=\frac{n^2+1}{n(a_n)}$

1. satellite73

i got my answer but apparently i was wrong this from @lopez_hatesmath

2. satellite73

maybe some fresh eyes would help

3. satellite73

nvm sorry to bother you

4. lopez_hatesmath

:(

5. satellite73

i got it

6. lopez_hatesmath

swagg

7. satellite73

it was this $a_1=\frac{3}{2}; a_{n+1}=\frac{n^2+1}{n}\times a_n$

8. satellite73

that is, the $$a_n$$ was in the NUMERATOR

9. satellite73

so now it is not so bad replace $$n=1$$ on the right hand side to get $$a_2$$

10. satellite73

you get $a_2=\frac{1^2+1}{1}\times \frac{3}{2}$ $a_2=2\times\frac{3}{2}$ $a_2=3$

11. satellite73

now replace $$n$$ by 2 on the right hand side to get $a_3=\frac{2^2+1}{2}\times 3$ $a_3=\frac{5}{2}\times 3$ $a_3=\frac{15}{2}$

12. satellite73

how are we doing so far?

13. lopez_hatesmath

good :)

14. satellite73

one more? $a_4=\frac{3^2+1}{3}\times \frac{15}{2}$ $a_4=\frac{10}{3}\times \frac{15}{2}$ $a_4=25$

15. lopez_hatesmath

okayy i got it!

16. satellite73

not so bad that is the idea, i thought the term was in the denominator which is why i was screwing it up

17. lopez_hatesmath

gotcha thanks for the help man.

18. satellite73

yw good luck with the next one, but it works the same so you should be good to go