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find the first 4 terms \[a_1=\frac{3}{2}; a_{n+1}=\frac{n^2+1}{n(a_n)}\]

Mathematics
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i got my answer but apparently i was wrong this from @lopez_hatesmath
maybe some fresh eyes would help
nvm sorry to bother you

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Other answers:

:(
i got it
swagg
it was this \[a_1=\frac{3}{2}; a_{n+1}=\frac{n^2+1}{n}\times a_n\]
that is, the \(a_n\) was in the NUMERATOR
so now it is not so bad replace \(n=1\) on the right hand side to get \(a_2\)
you get \[a_2=\frac{1^2+1}{1}\times \frac{3}{2}\] \[a_2=2\times\frac{3}{2}\] \[a_2=3\]
now replace \(n\) by 2 on the right hand side to get \[a_3=\frac{2^2+1}{2}\times 3\] \[a_3=\frac{5}{2}\times 3\] \[a_3=\frac{15}{2}\]
how are we doing so far?
good :)
one more? \[a_4=\frac{3^2+1}{3}\times \frac{15}{2}\] \[a_4=\frac{10}{3}\times \frac{15}{2}\] \[a_4=25\]
okayy i got it!
not so bad that is the idea, i thought the term was in the denominator which is why i was screwing it up
gotcha thanks for the help man.
yw good luck with the next one, but it works the same so you should be good to go

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