## zackb Group Title simplify by reducig the index of the radical 2 years ago 2 years ago

1. zackb

$\sqrt[12]{125x ^{3}}$

2. zzr0ck3r

= (125*x^3)^(1/12) - (5^3*x^3)^(1/12) = 5^(3/12)*x(^(3/12) = 5^(1/4)*x^(1/4) = (5x)^(1/4) = $\sqrt[4]{5x}$

3. zackb

thanks

4. Calcmathlete

Remember how you can rewrite it as a rational exponent. $\sqrt[12]{125x^3} \implies \sqrt[12]{(5x)^3} \implies (5x)^{\frac{3}{12}} \implies (5x)^{\frac14} \implies \sqrt[4]{5x}$See how it works? I just used this rule below: $\sqrt[n]{y^x} \implies y^{\frac xn}$