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Use the Quadratic Formula to solve the equation. -2x^2 - 5x + 5 = 0

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\[\LARGE Quadratic~Formula: x = \frac{-b ± \sqrt{b^2 - 4ac}}{2a}\]\[\large where,\]\[\large a = -2\]\[\large b = -5\]\[\large c = 5\]
\[x= -b \pm \sqrt{b^{2}-4ac}/2a\] put the values

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Other answers:

Lopez.. my answers dont look like that on the site
I still dont know how to do this.:/
\[-2x^2 - 5x + 5 = 0\]multiply by \(-1\) to make life nicer get \[2x^2 + 5x - 5 = 0\]use \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with \[a=2,b=-5,c=5\]
put the numbers in the slot,s, do the arithmetic carefully \[x=\frac{-(-5)\pm\sqrt{(-5)^2-4\times 1\times 5}}{2\times 2}\]
click on the alternate answers the answers are there
i got x approx -3.26556 and x approx 0.765564
I tried to work it out and i still dont see my answer'
|dw:1344713909733:dw| My answers look like this
what are your options?
That was A... hold on.
-5+or- sqrt of 5 all over 2
Thats not an option
\[\implies x = \frac{-(-5) ± \sqrt{(-5)^2 - 4(-2)(5)}}{2(-2)}\]\[ \implies x = \frac{5 ± \sqrt{25 + 40}}{-4}\]\[\implies x = -\frac{5 ± \sqrt{65}}{4}\]\[\implies x = -\frac54 ± \frac{\sqrt{65}}{4}\]Do you see how I got that based on my first post?
I think so. Thank you!
np :)

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