## anonymous 4 years ago Use the Quadratic Formula to solve the equation. -2x^2 - 5x + 5 = 0

1. anonymous

$\LARGE Quadratic~Formula: x = \frac{-b ± \sqrt{b^2 - 4ac}}{2a}$$\large where,$$\large a = -2$$\large b = -5$$\large c = 5$

2. anonymous
3. waleed_imtiaz

$x= -b \pm \sqrt{b^{2}-4ac}/2a$ put the values

4. anonymous

Lopez.. my answers dont look like that on the site

5. anonymous

I still dont know how to do this.:/

6. anonymous

$-2x^2 - 5x + 5 = 0$multiply by $$-1$$ to make life nicer get $2x^2 + 5x - 5 = 0$use $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ with $a=2,b=-5,c=5$

7. anonymous

put the numbers in the slot,s, do the arithmetic carefully $x=\frac{-(-5)\pm\sqrt{(-5)^2-4\times 1\times 5}}{2\times 2}$

8. anonymous

9. anonymous

i got x approx -3.26556 and x approx 0.765564

10. anonymous

I tried to work it out and i still dont see my answer'

11. anonymous

|dw:1344713909733:dw| My answers look like this

12. anonymous

13. anonymous

That was A... hold on.

14. anonymous

-5+or- sqrt of 5 all over 2

15. anonymous

|dw:1344714110752:dw|

16. anonymous

Thats not an option

17. anonymous

$\implies x = \frac{-(-5) ± \sqrt{(-5)^2 - 4(-2)(5)}}{2(-2)}$$\implies x = \frac{5 ± \sqrt{25 + 40}}{-4}$$\implies x = -\frac{5 ± \sqrt{65}}{4}$$\implies x = -\frac54 ± \frac{\sqrt{65}}{4}$Do you see how I got that based on my first post?

18. anonymous

I think so. Thank you!

19. anonymous

np :)

20. anonymous

swaggg