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EmilyJernigan Group Title

Use the Quadratic Formula to solve the equation. -2x^2 - 5x + 5 = 0

  • 2 years ago
  • 2 years ago

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  1. Calcmathlete Group Title
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    \[\LARGE Quadratic~Formula: x = \frac{-b ± \sqrt{b^2 - 4ac}}{2a}\]\[\large where,\]\[\large a = -2\]\[\large b = -5\]\[\large c = 5\]

    • 2 years ago
  2. lopez_hatesmath Group Title
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    http://www.wolframalpha.com/input/?i=-2x%5E2+-+5x+%2B+5+%3D+0

    • 2 years ago
  3. waleed_imtiaz Group Title
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    \[x= -b \pm \sqrt{b^{2}-4ac}/2a\] put the values

    • 2 years ago
  4. EmilyJernigan Group Title
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    Lopez.. my answers dont look like that on the site

    • 2 years ago
  5. EmilyJernigan Group Title
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    I still dont know how to do this.:/

    • 2 years ago
  6. satellite73 Group Title
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    \[-2x^2 - 5x + 5 = 0\]multiply by \(-1\) to make life nicer get \[2x^2 + 5x - 5 = 0\]use \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with \[a=2,b=-5,c=5\]

    • 2 years ago
  7. satellite73 Group Title
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    put the numbers in the slot,s, do the arithmetic carefully \[x=\frac{-(-5)\pm\sqrt{(-5)^2-4\times 1\times 5}}{2\times 2}\]

    • 2 years ago
  8. lopez_hatesmath Group Title
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    click on the alternate answers the answers are there

    • 2 years ago
  9. lopez_hatesmath Group Title
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    i got x approx -3.26556 and x approx 0.765564

    • 2 years ago
  10. EmilyJernigan Group Title
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    I tried to work it out and i still dont see my answer'

    • 2 years ago
  11. EmilyJernigan Group Title
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    |dw:1344713909733:dw| My answers look like this

    • 2 years ago
  12. lopez_hatesmath Group Title
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    what are your options?

    • 2 years ago
  13. EmilyJernigan Group Title
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    That was A... hold on.

    • 2 years ago
  14. lopez_hatesmath Group Title
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    -5+or- sqrt of 5 all over 2

    • 2 years ago
  15. EmilyJernigan Group Title
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    |dw:1344714110752:dw|

    • 2 years ago
  16. EmilyJernigan Group Title
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    Thats not an option

    • 2 years ago
  17. Calcmathlete Group Title
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    \[\implies x = \frac{-(-5) ± \sqrt{(-5)^2 - 4(-2)(5)}}{2(-2)}\]\[ \implies x = \frac{5 ± \sqrt{25 + 40}}{-4}\]\[\implies x = -\frac{5 ± \sqrt{65}}{4}\]\[\implies x = -\frac54 ± \frac{\sqrt{65}}{4}\]Do you see how I got that based on my first post?

    • 2 years ago
  18. EmilyJernigan Group Title
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    I think so. Thank you!

    • 2 years ago
  19. Calcmathlete Group Title
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    np :)

    • 2 years ago
  20. lopez_hatesmath Group Title
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    swaggg

    • 2 years ago
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