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manamesasher
Group Title
Solve the following system of equations graphically, find the graph
2x y = 1
x + y = 2
 one year ago
 one year ago
manamesasher Group Title
Solve the following system of equations graphically, find the graph 2x y = 1 x + y = 2
 one year ago
 one year ago

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Calcmathlete Group TitleBest ResponseYou've already chosen the best response.3
Easiest way to do this is to plug in the point of intersection and if both equations are true, then it's the correct answer. For instance, let's check 2. \[2x  y = 1\]\[2(1)  (1) = 1\]\[2 + 1 = 1\]\[3 ≠ 1\]THerefore, it isn't 2.
 one year ago

manamesasher Group TitleBest ResponseYou've already chosen the best response.0
i was talking about the graph...
 one year ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.3
Also, if the point of intersection is the same in two choices, then you have to make sure the lines make sense.
 one year ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.3
And yes, 2 is incorrect since the solution set is also the point of intersection when graphed...
 one year ago

manamesasher Group TitleBest ResponseYou've already chosen the best response.0
how about 3?..
 one year ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.3
Are you just guessing at this point?
 one year ago

manamesasher Group TitleBest ResponseYou've already chosen the best response.0
no i'm asking if you can help me solve it...
 one year ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.3
Alright. I explained the process above... Let's take a look at choice 3... 2x  y = 1 Plus in the point of intersection, (1, 1) 2(1)  (1) = 1 2  1 = 1 3 ≠ 1 Do you see how the final equations ends up false since 3 does NOT equal 1?
 one year ago

manamesasher Group TitleBest ResponseYou've already chosen the best response.0
ok. and choice 1, (1, 1) 2(1)(1)=1
 one year ago

manamesasher Group TitleBest ResponseYou've already chosen the best response.0
1+1=2
 one year ago

manamesasher Group TitleBest ResponseYou've already chosen the best response.0
so it is choice 1..
 one year ago

manamesasher Group TitleBest ResponseYou've already chosen the best response.0
thank you...
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
my idea would be to use a knowledge of the equations to match the graph in this manner x + y = 2 notice this is pretty easy to turn to y = mx+b format y = x2 we need to find an option that has a line going thru y=2 and a downill slope of 1
 one year ago

Calcmathlete Group TitleBest ResponseYou've already chosen the best response.3
Um... \[2(1)  (1) = 1\]\[2 + 1 = 1\]\[1 = 1\]You should always check both equations by the way for the future, but it is indeed choice 1 :)
 one year ago

manamesasher Group TitleBest ResponseYou've already chosen the best response.0
oh, ok sorry.. thanks again...
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
1 and 3 fit the thru 2 part; and 3 is too steep for comfort
 one year ago

robtobey Group TitleBest ResponseYou've already chosen the best response.0
A plot is attached.
 one year ago
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