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sasogeek
 2 years ago
Best ResponseYou've already chosen the best response.2do you know the laws of logs?

IloveCharlie
 2 years ago
Best ResponseYou've already chosen the best response.0I'm faimiliar with them, yes

sasogeek
 2 years ago
Best ResponseYou've already chosen the best response.2ok so one of them says that when you have log(a/b), it is the same as log(a)log(b) ... you can apply that hear :)

IloveCharlie
 2 years ago
Best ResponseYou've already chosen the best response.0Yes, I understand. Thanks!

sasogeek
 2 years ago
Best ResponseYou've already chosen the best response.2what did you get though?

Hero
 2 years ago
Best ResponseYou've already chosen the best response.0Didn't you post this same problem the other day @IloveCharlie

Hero
 2 years ago
Best ResponseYou've already chosen the best response.0\(\text{Latex is working}\)

sasogeek
 2 years ago
Best ResponseYou've already chosen the best response.2/(/large hi /) ... if this doesn't appear correctly, then i probably forgot how to write latex, if not, yay! else, :(

sasogeek
 2 years ago
Best ResponseYou've already chosen the best response.2ok so it messed up.... what did i do wrong?

IloveCharlie
 2 years ago
Best ResponseYou've already chosen the best response.0:/ I'm having trouble...

sasogeek
 2 years ago
Best ResponseYou've already chosen the best response.2\(found \ what \ i \ did \ wrong \ \text{:P} \) anyway what are you having trouble with?

IloveCharlie
 2 years ago
Best ResponseYou've already chosen the best response.0Is it log(3.8)log(5)?

IloveCharlie
 2 years ago
Best ResponseYou've already chosen the best response.0@Hero Hmm... no. If so, that'd be weird. I don't think my Precal/Trig online course would repeat problems. Maybe it was something similar?

bamkey360
 2 years ago
Best ResponseYou've already chosen the best response.0u said what it equal to

sasogeek
 2 years ago
Best ResponseYou've already chosen the best response.2actually, no. the question has a quotient/division thingy, which obviously means there's two sides to it. one is \(\large \sqrt{(3.2)(4.7)} \) and the other is \(\large 5 \) according to the law, \(\large log(\frac{a}{b})=log(a)  log(b) \) in this case, a= \(\large \sqrt{(3.2)(4.7)} \) and b = \(\large 5 \) hence: \(\large log(\frac{\sqrt{(3.2)(4.7)}}{5})=log(\sqrt{(3.2)(4.7)})  log(5) \) =\(\large log(\sqrt{(15.04)} \ )log(5) \)

IloveCharlie
 2 years ago
Best ResponseYou've already chosen the best response.0Ohhhh o.k. Now I get it. Thanks so much sasogeek

sasogeek
 2 years ago
Best ResponseYou've already chosen the best response.2no problem :) you're welcome x
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