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sasogeekBest ResponseYou've already chosen the best response.2
do you know the laws of logs?
 one year ago

IloveCharlieBest ResponseYou've already chosen the best response.0
I'm faimiliar with them, yes
 one year ago

sasogeekBest ResponseYou've already chosen the best response.2
ok so one of them says that when you have log(a/b), it is the same as log(a)log(b) ... you can apply that hear :)
 one year ago

IloveCharlieBest ResponseYou've already chosen the best response.0
Yes, I understand. Thanks!
 one year ago

sasogeekBest ResponseYou've already chosen the best response.2
what did you get though?
 one year ago

HeroBest ResponseYou've already chosen the best response.0
Didn't you post this same problem the other day @IloveCharlie
 one year ago

HeroBest ResponseYou've already chosen the best response.0
\(\text{Latex is working}\)
 one year ago

sasogeekBest ResponseYou've already chosen the best response.2
/(/large hi /) ... if this doesn't appear correctly, then i probably forgot how to write latex, if not, yay! else, :(
 one year ago

sasogeekBest ResponseYou've already chosen the best response.2
ok so it messed up.... what did i do wrong?
 one year ago

IloveCharlieBest ResponseYou've already chosen the best response.0
:/ I'm having trouble...
 one year ago

sasogeekBest ResponseYou've already chosen the best response.2
\(found \ what \ i \ did \ wrong \ \text{:P} \) anyway what are you having trouble with?
 one year ago

IloveCharlieBest ResponseYou've already chosen the best response.0
Is it log(3.8)log(5)?
 one year ago

IloveCharlieBest ResponseYou've already chosen the best response.0
@Hero Hmm... no. If so, that'd be weird. I don't think my Precal/Trig online course would repeat problems. Maybe it was something similar?
 one year ago

bamkey360Best ResponseYou've already chosen the best response.0
u said what it equal to
 one year ago

sasogeekBest ResponseYou've already chosen the best response.2
actually, no. the question has a quotient/division thingy, which obviously means there's two sides to it. one is \(\large \sqrt{(3.2)(4.7)} \) and the other is \(\large 5 \) according to the law, \(\large log(\frac{a}{b})=log(a)  log(b) \) in this case, a= \(\large \sqrt{(3.2)(4.7)} \) and b = \(\large 5 \) hence: \(\large log(\frac{\sqrt{(3.2)(4.7)}}{5})=log(\sqrt{(3.2)(4.7)})  log(5) \) =\(\large log(\sqrt{(15.04)} \ )log(5) \)
 one year ago

IloveCharlieBest ResponseYou've already chosen the best response.0
Ohhhh o.k. Now I get it. Thanks so much sasogeek
 one year ago

sasogeekBest ResponseYou've already chosen the best response.2
no problem :) you're welcome x
 one year ago
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