## lawls 3 years ago If the sides of a right triangle have lengths of x-7, x an x+1, then x= (a) (1, 7) (b) (7, -1) (c) (7, 4) (d) (7, 12) (e) (4, 12)

1. sauravshakya

first tell me which is the longest side

2. sauravshakya

x-7,x,x+1....... what do u thik have the biggest value

3. ParthKohli

Hint: Work with the dearest Pythagorean Theorem.

4. sauravshakya

But beofre using Pythagorean Theorem.. u must find the longest side

5. Calcmathlete

Obviously, x + 1 would be the largest side and therefore the hypotenuse because of the + 1 while x is neutral and -7 is negative. THerefore, now use Pythagorean THeorem. \[c^2 = a^2 + b^2\]\[(x + 1)^2 = x^2 + (x - 7)^2\]\[x^2 + 2x + 1 = x^2 + x^2 - 14x + 49\]\[x^2 + 2x + 1 = 2x^2 - 14x + 49\]\[0 = x^2 - 16x + 48\]Can you figure out how to solve the4 quadratic from here?

6. ParthKohli

Yes sir! Yes sir!

7. lawls

i got x = 4, 12

8. lawls

so answer choice (e) is right?

9. ParthKohli

You, sir, are totally correct!

10. Calcmathlete

Kinda ironic since 12 is the only true solution, but whatever works ^_^

11. lawls

thanks

12. Calcmathlete

np :)