anonymous
  • anonymous
If the sides of a right triangle have lengths of x-7, x an x+1, then x= (a) (1, 7) (b) (7, -1) (c) (7, 4) (d) (7, 12) (e) (4, 12)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
first tell me which is the longest side
anonymous
  • anonymous
x-7,x,x+1....... what do u thik have the biggest value
ParthKohli
  • ParthKohli
Hint: Work with the dearest Pythagorean Theorem.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
But beofre using Pythagorean Theorem.. u must find the longest side
anonymous
  • anonymous
Obviously, x + 1 would be the largest side and therefore the hypotenuse because of the + 1 while x is neutral and -7 is negative. THerefore, now use Pythagorean THeorem. \[c^2 = a^2 + b^2\]\[(x + 1)^2 = x^2 + (x - 7)^2\]\[x^2 + 2x + 1 = x^2 + x^2 - 14x + 49\]\[x^2 + 2x + 1 = 2x^2 - 14x + 49\]\[0 = x^2 - 16x + 48\]Can you figure out how to solve the4 quadratic from here?
ParthKohli
  • ParthKohli
Yes sir! Yes sir!
anonymous
  • anonymous
i got x = 4, 12
anonymous
  • anonymous
so answer choice (e) is right?
ParthKohli
  • ParthKohli
You, sir, are totally correct!
anonymous
  • anonymous
Kinda ironic since 12 is the only true solution, but whatever works ^_^
anonymous
  • anonymous
thanks
anonymous
  • anonymous
np :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.