Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

|dw:1344742023146:dw|
\[\frac{u^2}{(w-2)^2}=v\]Implied domain w!=2 \[u^2=v(w-2)^2\]Multiplied (w-2) on both sides
Now. What do you think we divide by on both sideS?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

v?
yes. You get: \[u/v = (w-2)^2\] Now you need to perform a certain operation to both sides to get rid of the ^2...
square root
Yes. You get: \[\sqrt{u/v}=\sqrt{(w-2)^2}\]
Now, what's sqrt(x^2)=?
I assume you're in reals domain
yeah i am and just x
Not quite. what's sqrt((-5)^2)?
25
no...
5
yes. And now that you've seen that, what do you think sqrt(x^2) is? it's not just x, since then the answer to sqrt((-5)^2) would be -5...
+/- x
Well, sort of. For \[x \epsilon R\]\[\sqrt{x^2}=|x|\]
But anyways, whats our 'x' in the problem?
is the answer w=2v +-u√(v)
Well what I got was \[\pm \sqrt{u/v}-2\]
|dw:1344743061685:dw| what about this
That's the same thing.
i htought yours was a negative 2
Oh yeah it was . Typo, my bad.
so is my picture correct?
Yeah.
thanks

Not the answer you are looking for?

Search for more explanations.

Ask your own question