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anonymous
 4 years ago
solve for w.
anonymous
 4 years ago
solve for w.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1344742023146:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{u^2}{(w2)^2}=v\]Implied domain w!=2 \[u^2=v(w2)^2\]Multiplied (w2) on both sides

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now. What do you think we divide by on both sideS?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes. You get: \[u/v = (w2)^2\] Now you need to perform a certain operation to both sides to get rid of the ^2...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes. You get: \[\sqrt{u/v}=\sqrt{(w2)^2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now, what's sqrt(x^2)=?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I assume you're in reals domain

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Not quite. what's sqrt((5)^2)?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes. And now that you've seen that, what do you think sqrt(x^2) is? it's not just x, since then the answer to sqrt((5)^2) would be 5...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, sort of. For \[x \epsilon R\]\[\sqrt{x^2}=x\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But anyways, whats our 'x' in the problem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is the answer w=2v +u√(v)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well what I got was \[\pm \sqrt{u/v}2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1344743061685:dw what about this

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That's the same thing.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i htought yours was a negative 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh yeah it was . Typo, my bad.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so is my picture correct?
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