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storyw4
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dw:1344742023146:dw

vf321
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\[\frac{u^2}{(w2)^2}=v\]Implied domain w!=2
\[u^2=v(w2)^2\]Multiplied (w2) on both sides

vf321
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Now. What do you think we divide by on both sideS?

storyw4
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v?

vf321
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yes. You get:
\[u/v = (w2)^2\]
Now you need to perform a certain operation to both sides to get rid of the ^2...

storyw4
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square root

vf321
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Yes. You get:
\[\sqrt{u/v}=\sqrt{(w2)^2}\]

vf321
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Now, what's sqrt(x^2)=?

vf321
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I assume you're in reals domain

storyw4
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yeah i am and just x

vf321
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Not quite. what's sqrt((5)^2)?

storyw4
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25

vf321
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no...

storyw4
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5

vf321
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yes. And now that you've seen that, what do you think sqrt(x^2) is? it's not just x, since then the answer to sqrt((5)^2) would be 5...

storyw4
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+/ x

vf321
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Well, sort of. For
\[x \epsilon R\]\[\sqrt{x^2}=x\]

vf321
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But anyways, whats our 'x' in the problem?

storyw4
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is the answer w=2v +u√(v)

vf321
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Well what I got was
\[\pm \sqrt{u/v}2\]

storyw4
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dw:1344743061685:dw
what about this

vf321
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That's the same thing.

storyw4
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i htought yours was a negative 2

vf321
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Oh yeah it was . Typo, my bad.

storyw4
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so is my picture correct?

vf321
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Yeah.

storyw4
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thanks