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|dw:1344742023146:dw|

\[\frac{u^2}{(w-2)^2}=v\]Implied domain w!=2
\[u^2=v(w-2)^2\]Multiplied (w-2) on both sides

Now. What do you think we divide by on both sideS?

v?

square root

Yes. You get:
\[\sqrt{u/v}=\sqrt{(w-2)^2}\]

Now, what's sqrt(x^2)=?

I assume you're in reals domain

yeah i am and just x

Not quite. what's sqrt((-5)^2)?

25

no...

+/- x

Well, sort of. For
\[x \epsilon R\]\[\sqrt{x^2}=|x|\]

But anyways, whats our 'x' in the problem?

is the answer w=2v +-u√(v)

Well what I got was
\[\pm \sqrt{u/v}-2\]

|dw:1344743061685:dw|
what about this

That's the same thing.

i htought yours was a negative 2

Oh yeah it was . Typo, my bad.

so is my picture correct?

Yeah.

thanks