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ranyai12 Group Title

Help Please! if the location of a particular electron can be measured only to a precision of 0.058nm, what is the minimum uncertainty in the electrons velocity?

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    @.Sam.

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    The heisenberg uncertainty principle is just: \[x*p \ge \hbar/2\] So here you have the constant h bar, x is position, p is momentum which if you remember is just p=mv. The mass of the electron is another constant. Simply solve for your minimum uncertainty!

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