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LaurenAshley1201 Group Title

help :) multiply expression

  • one year ago
  • one year ago

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  1. LaurenAshley1201 Group Title
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    \[2\sqrt{6}\times \sqrt{10}\]

    • one year ago
  2. Calcmathlete Group Title
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    Multiply them seperately... \[2\sqrt6 \times \sqrt{10} \implies 2\sqrt{6 \times 10} \implies 2 \sqrt{2 \times 3 \times 2 \times 5} \implies~?\]

    • one year ago
  3. Calcmathlete Group Title
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    Can you finish from there? Can you simplify the radical?

    • one year ago
  4. violy Group Title
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    |dw:1344751807375:dw| here is an example. :)

    • one year ago
  5. waterineyes Group Title
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    @merp it is better if you do it here by your own..

    • one year ago
  6. waterineyes Group Title
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    @LaurenAshley1201 \[\implies 2 \sqrt{\color{blue}{\underline{2 \times 2}} \times 3 \times 5} = ??\]

    • one year ago
  7. LaurenAshley1201 Group Title
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    2 sqrt 60? i dont think im doing it right

    • one year ago
  8. waterineyes Group Title
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    You can solve further for \(\sqrt{60}\)..

    • one year ago
  9. LaurenAshley1201 Group Title
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    2 sqrt 15

    • one year ago
  10. waterineyes Group Title
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    \[\sqrt{60} = \sqrt{\color{blue}{\underline{2 \times 2}} \times 3 \times 5}\] Can you go further..??

    • one year ago
  11. violy Group Title
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    think of a perfect square number that can go into 60.

    • one year ago
  12. waterineyes Group Title
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    Yes..

    • one year ago
  13. waterineyes Group Title
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    There is one 2 outside too..

    • one year ago
  14. Calcmathlete Group Title
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    We have broken 60 down into prime factors for you. Remember this? \[\sqrt{x \times x} = x\]Use the same rule...

    • one year ago
  15. waterineyes Group Title
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    \[2 \times 2 \sqrt{15} = ??\]

    • one year ago
  16. violy Group Title
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    do you mean sqrt (4 * 15) ?

    • one year ago
  17. waterineyes Group Title
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    No..

    • one year ago
  18. LaurenAshley1201 Group Title
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    i dont know how to go any furhter

    • one year ago
  19. waterineyes Group Title
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    \(\sqrt{60}\) is how much ??

    • one year ago
  20. waterineyes Group Title
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    you have solved it above..

    • one year ago
  21. waterineyes Group Title
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    \[\sqrt{60} = \sqrt{\color{blue}{\underline{2 \times 2}} \times 3 \times 5} = ??\]

    • one year ago
  22. violy Group Title
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    its like sqrt( 5 x 5) = sqrt (25) = 5.

    • one year ago
  23. waterineyes Group Title
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    Where are you having problem @LaurenAshley1201

    • one year ago
  24. violy Group Title
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    let me give you an example: \[\sqrt{45}=\sqrt{3*3*5}=\sqrt{9} * \sqrt{5} = 3\sqrt{5}\]

    • one year ago
  25. LaurenAshley1201 Group Title
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    sqrt of 60 is 2 sqrt 15

    • one year ago
  26. violy Group Title
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    you got it right now! :)

    • one year ago
  27. waterineyes Group Title
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    In square root you can pull out one from a pair like this: \[\sqrt{4 \times 4 \times 5}\] Here you can see there are two 4's. SO you can take one 4 outside and there will remain no 4 in the square root brackets: So it becomes; \[\sqrt{\color{green}{\underline{ 4 \times 4} \times 5}} \implies 4 \sqrt{5}\]

    • one year ago
  28. Calcmathlete Group Title
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    Ok. Do you understand this at the very least? \[\sqrt{3 \times 3} = \sqrt{3^2} = \sqrt{9} = 3\color{red}{\huge??????}\]

    • one year ago
  29. LaurenAshley1201 Group Title
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    yes i do

    • one year ago
  30. Calcmathlete Group Title
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    THat's basically what you're doing here, it's just that you can make sense of it without showing all of the steps because you know the end result which is why we know that\[\sqrt{60} = \sqrt{2 \times 2 \times 3 \times 5} = 2\sqrt{15}\]

    • one year ago
  31. waterineyes Group Title
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    \[2 \sqrt{60} = 2 \times (2 \sqrt{15}) = ??\]

    • one year ago
  32. LaurenAshley1201 Group Title
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    @Calcmathlete would that be my final answer?

    • one year ago
  33. Calcmathlete Group Title
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    Not quite...you forgot the 2 that was already out there... \[2 \times 2\sqrt{15} = ?\]

    • one year ago
  34. violy Group Title
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    not yet, example: \[3*(4\sqrt{5}) = 3*4\sqrt{5} = 12\sqrt{5}\]

    • one year ago
  35. LaurenAshley1201 Group Title
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    i figuired it out,with everyones help ! thanks everyone

    • one year ago
  36. Calcmathlete Group Title
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    Glad to help :)

    • one year ago
  37. violy Group Title
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    my pleasure :)

    • one year ago
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