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LaurenAshley1201 Group Title

help :) multiply expression

  • 2 years ago
  • 2 years ago

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  1. LaurenAshley1201 Group Title
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    \[2\sqrt{6}\times \sqrt{10}\]

    • 2 years ago
  2. Calcmathlete Group Title
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    Multiply them seperately... \[2\sqrt6 \times \sqrt{10} \implies 2\sqrt{6 \times 10} \implies 2 \sqrt{2 \times 3 \times 2 \times 5} \implies~?\]

    • 2 years ago
  3. Calcmathlete Group Title
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    Can you finish from there? Can you simplify the radical?

    • 2 years ago
  4. violy Group Title
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    |dw:1344751807375:dw| here is an example. :)

    • 2 years ago
  5. waterineyes Group Title
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    @merp it is better if you do it here by your own..

    • 2 years ago
  6. waterineyes Group Title
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    @LaurenAshley1201 \[\implies 2 \sqrt{\color{blue}{\underline{2 \times 2}} \times 3 \times 5} = ??\]

    • 2 years ago
  7. LaurenAshley1201 Group Title
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    2 sqrt 60? i dont think im doing it right

    • 2 years ago
  8. waterineyes Group Title
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    You can solve further for \(\sqrt{60}\)..

    • 2 years ago
  9. LaurenAshley1201 Group Title
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    2 sqrt 15

    • 2 years ago
  10. waterineyes Group Title
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    \[\sqrt{60} = \sqrt{\color{blue}{\underline{2 \times 2}} \times 3 \times 5}\] Can you go further..??

    • 2 years ago
  11. violy Group Title
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    think of a perfect square number that can go into 60.

    • 2 years ago
  12. waterineyes Group Title
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    Yes..

    • 2 years ago
  13. waterineyes Group Title
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    There is one 2 outside too..

    • 2 years ago
  14. Calcmathlete Group Title
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    We have broken 60 down into prime factors for you. Remember this? \[\sqrt{x \times x} = x\]Use the same rule...

    • 2 years ago
  15. waterineyes Group Title
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    \[2 \times 2 \sqrt{15} = ??\]

    • 2 years ago
  16. violy Group Title
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    do you mean sqrt (4 * 15) ?

    • 2 years ago
  17. waterineyes Group Title
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    No..

    • 2 years ago
  18. LaurenAshley1201 Group Title
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    i dont know how to go any furhter

    • 2 years ago
  19. waterineyes Group Title
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    \(\sqrt{60}\) is how much ??

    • 2 years ago
  20. waterineyes Group Title
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    you have solved it above..

    • 2 years ago
  21. waterineyes Group Title
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    \[\sqrt{60} = \sqrt{\color{blue}{\underline{2 \times 2}} \times 3 \times 5} = ??\]

    • 2 years ago
  22. violy Group Title
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    its like sqrt( 5 x 5) = sqrt (25) = 5.

    • 2 years ago
  23. waterineyes Group Title
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    Where are you having problem @LaurenAshley1201

    • 2 years ago
  24. violy Group Title
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    let me give you an example: \[\sqrt{45}=\sqrt{3*3*5}=\sqrt{9} * \sqrt{5} = 3\sqrt{5}\]

    • 2 years ago
  25. LaurenAshley1201 Group Title
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    sqrt of 60 is 2 sqrt 15

    • 2 years ago
  26. violy Group Title
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    you got it right now! :)

    • 2 years ago
  27. waterineyes Group Title
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    In square root you can pull out one from a pair like this: \[\sqrt{4 \times 4 \times 5}\] Here you can see there are two 4's. SO you can take one 4 outside and there will remain no 4 in the square root brackets: So it becomes; \[\sqrt{\color{green}{\underline{ 4 \times 4} \times 5}} \implies 4 \sqrt{5}\]

    • 2 years ago
  28. Calcmathlete Group Title
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    Ok. Do you understand this at the very least? \[\sqrt{3 \times 3} = \sqrt{3^2} = \sqrt{9} = 3\color{red}{\huge??????}\]

    • 2 years ago
  29. LaurenAshley1201 Group Title
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    yes i do

    • 2 years ago
  30. Calcmathlete Group Title
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    THat's basically what you're doing here, it's just that you can make sense of it without showing all of the steps because you know the end result which is why we know that\[\sqrt{60} = \sqrt{2 \times 2 \times 3 \times 5} = 2\sqrt{15}\]

    • 2 years ago
  31. waterineyes Group Title
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    \[2 \sqrt{60} = 2 \times (2 \sqrt{15}) = ??\]

    • 2 years ago
  32. LaurenAshley1201 Group Title
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    @Calcmathlete would that be my final answer?

    • 2 years ago
  33. Calcmathlete Group Title
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    Not quite...you forgot the 2 that was already out there... \[2 \times 2\sqrt{15} = ?\]

    • 2 years ago
  34. violy Group Title
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    not yet, example: \[3*(4\sqrt{5}) = 3*4\sqrt{5} = 12\sqrt{5}\]

    • 2 years ago
  35. LaurenAshley1201 Group Title
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    i figuired it out,with everyones help ! thanks everyone

    • 2 years ago
  36. Calcmathlete Group Title
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    Glad to help :)

    • 2 years ago
  37. violy Group Title
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    my pleasure :)

    • 2 years ago
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