anonymous
  • anonymous
help :) multiply expression
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[2\sqrt{6}\times \sqrt{10}\]
anonymous
  • anonymous
Multiply them seperately... \[2\sqrt6 \times \sqrt{10} \implies 2\sqrt{6 \times 10} \implies 2 \sqrt{2 \times 3 \times 2 \times 5} \implies~?\]
anonymous
  • anonymous
Can you finish from there? Can you simplify the radical?

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anonymous
  • anonymous
|dw:1344751807375:dw| here is an example. :)
anonymous
  • anonymous
@merp it is better if you do it here by your own..
anonymous
  • anonymous
@LaurenAshley1201 \[\implies 2 \sqrt{\color{blue}{\underline{2 \times 2}} \times 3 \times 5} = ??\]
anonymous
  • anonymous
2 sqrt 60? i dont think im doing it right
anonymous
  • anonymous
You can solve further for \(\sqrt{60}\)..
anonymous
  • anonymous
2 sqrt 15
anonymous
  • anonymous
\[\sqrt{60} = \sqrt{\color{blue}{\underline{2 \times 2}} \times 3 \times 5}\] Can you go further..??
anonymous
  • anonymous
think of a perfect square number that can go into 60.
anonymous
  • anonymous
Yes..
anonymous
  • anonymous
There is one 2 outside too..
anonymous
  • anonymous
We have broken 60 down into prime factors for you. Remember this? \[\sqrt{x \times x} = x\]Use the same rule...
anonymous
  • anonymous
\[2 \times 2 \sqrt{15} = ??\]
anonymous
  • anonymous
do you mean sqrt (4 * 15) ?
anonymous
  • anonymous
No..
anonymous
  • anonymous
i dont know how to go any furhter
anonymous
  • anonymous
\(\sqrt{60}\) is how much ??
anonymous
  • anonymous
you have solved it above..
anonymous
  • anonymous
\[\sqrt{60} = \sqrt{\color{blue}{\underline{2 \times 2}} \times 3 \times 5} = ??\]
anonymous
  • anonymous
its like sqrt( 5 x 5) = sqrt (25) = 5.
anonymous
  • anonymous
Where are you having problem @LaurenAshley1201
anonymous
  • anonymous
let me give you an example: \[\sqrt{45}=\sqrt{3*3*5}=\sqrt{9} * \sqrt{5} = 3\sqrt{5}\]
anonymous
  • anonymous
sqrt of 60 is 2 sqrt 15
anonymous
  • anonymous
you got it right now! :)
anonymous
  • anonymous
In square root you can pull out one from a pair like this: \[\sqrt{4 \times 4 \times 5}\] Here you can see there are two 4's. SO you can take one 4 outside and there will remain no 4 in the square root brackets: So it becomes; \[\sqrt{\color{green}{\underline{ 4 \times 4} \times 5}} \implies 4 \sqrt{5}\]
anonymous
  • anonymous
Ok. Do you understand this at the very least? \[\sqrt{3 \times 3} = \sqrt{3^2} = \sqrt{9} = 3\color{red}{\huge??????}\]
anonymous
  • anonymous
yes i do
anonymous
  • anonymous
THat's basically what you're doing here, it's just that you can make sense of it without showing all of the steps because you know the end result which is why we know that\[\sqrt{60} = \sqrt{2 \times 2 \times 3 \times 5} = 2\sqrt{15}\]
anonymous
  • anonymous
\[2 \sqrt{60} = 2 \times (2 \sqrt{15}) = ??\]
anonymous
  • anonymous
@Calcmathlete would that be my final answer?
anonymous
  • anonymous
Not quite...you forgot the 2 that was already out there... \[2 \times 2\sqrt{15} = ?\]
anonymous
  • anonymous
not yet, example: \[3*(4\sqrt{5}) = 3*4\sqrt{5} = 12\sqrt{5}\]
anonymous
  • anonymous
i figuired it out,with everyones help ! thanks everyone
anonymous
  • anonymous
Glad to help :)
anonymous
  • anonymous
my pleasure :)

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