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anonymous
 4 years ago
Find the condition that x^n + y^n may be divisible by x + y.
anonymous
 4 years ago
Find the condition that x^n + y^n may be divisible by x + y.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How do you prove that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sum of odd roots factor always factor out (x+y)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What do you mean by that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know how, PLZ wait sec trying to write it down

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh got it.... let f(x)=x^n + y^n

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So you should use factor theorem for this?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now, when f(x) is divided by (x+y) then REMAINDER = f(y) = (y)^n + y^n

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now, for x^n + y^n to be divisible by x + y.. remainder = 0 or, (y)^n + y^n=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0which is only possible when n is odd

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so when n is odd, (y)^n = y so (y)^n + y^n = y + y = 0 thanks!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh its like this: when n is odd, (y)^n = (y)^n so (y)^n + y^n = (y)^n + y^n = 0
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