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funfun123456
4. Which of these if statements will evaluate to true? Assume that x = 5, and y = 10. if(!(y > x) || (x % y == x)) { Debug.Log("True 1"); } if( true || false ) { Debug.Log("True 2"); } if((y % x == 0) && (x < y) && (y - x != x)) { Debug.Log("True 3"); } 1 and 2 2 and 3
i have 1 & 2 as the answer
sorry its also in java script
9. When would you use an Array while programming? To conserve variable names by combining them into one variable To go with a for loop, since they work well together To represent a chess board and the locations of all of the pieces All of the above None of the above
You're welcome, it's like that : I will explain just one example, we will take the 3rd : if((y % x == 0) && (x < y) && (y - x != x)) { Debug.Log("True 3"); } (y % x == 0) --> This mean Y=10 modulo x=5 equal 0, true. (x < y) --> This mean 5 < 10, true. (y - x != x) --> This mean (10-5) different than 5, false. && --> This means And So we have (True && True && False) = False. Good luck.
I think the 2nd, mean to use it with a for loop.
wouldnt you also use an array for combining them into one var
I am not sure if I understand this one well, but usually the array has the same type of data for all its cells, so I really dunno. But I DON'T think so.
I think all of the above "To conserve variable names by combining them into one variable" I think it tries to say that instead row1 row2 row3 row4 we can just have row[] array "To go with a for loop, since they work well together" well you just go by indexes in for loop "To represent a chess board and the locations of all of the pieces" You can represent chess board by 2D array, cell[row][column]
if(!(y > x) || (x % y == x)) { Debug.Log("True 1"); } !(10>5) will be false 5 % 10 = 5 because 5 divided by 10 u get 0 and remainder is 5, so this is true false or true is true so first is true if( true || false ) { Debug.Log("True 2"); } true or false is true so second is true as well if((y % x == 0) && (x < y) && (y - x != x)) { Debug.Log("True 3"); } 10 % 5 = 0 10 divided by 5 is 2 and remainder is 0 so this is true 5 < 10 its true 10-5 != 5, 5 equals 5 so its false true and true and false is false answer is 1st and 2nd true
Ah yeah 5 % 10 = 5, true, I make a mistake I wrote 5%10 but I was solving 10 % 5 !!!!
its only 2 for in 1 both statements must be false for in "or statements" one becomes true then everything is true there is this ! sign which will alternate the sign so imagine it like this !x == true||1 x should be 0 or FALSE so if it is inverted it will result to a 1 or true in number 3 it is an and statement if one statement fails then the statements under that certain condition will be skipped. it was skipped for (y - x != x) which is 10 - 5 != 5 we all know that 10 - 5 == 5 so its FALSE So the ANSWER is "2" xD hope it's clear to you xD
@lemuelpogi dont forget ! has biggest priority..
it has the highest priority but it will look to it later on after the operations and or etc.
no it wont because you said urself it has highest priority, if you don't believe type it in any programming language and see it urself
i mean operations will be calculated then the comparisons like = <> etc. then the and or
but ! has higher priority than = < > and higher priority than 'and' 'or'
it has a higher priority but it is used as getting only the inverse after calculating the answer on either sides xD
no its used as soon as you can since it has highest priority, so you evaluate whats in brackets and then immediately inverse it (10>5) is true !(10>5) is false
that's quite true xD
so ur answer is incorrect then
huh? in which part??? ITS TRUE
so u saying that 5%10==5 is true?
yes definitely you can not divide 5 by 10 so its a remainder xD
u said that true is only 2, but first one is true too so thats why u were incorrect
1 and 2 will evaluate to true. because y>x will be true but due to ! it will be false. x%y evaluates to 5 and 5==5 will be true. Since both the expressions are connected by OR.So the result will be true. The second case is same as first.
u r write @Tomas.A i made 10 mod 5 and its the opposite