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find the solution set of the equation 3(sec x1)= 5 sec x in the interval of 0< x<2 pi.
A) pi/3 and 5pi/3
B) pi/6 and 11pi/6
C) pi/6 and 5pi/6
D) pi/3 and 2pi/3
 one year ago
 one year ago
find the solution set of the equation 3(sec x1)= 5 sec x in the interval of 0< x<2 pi. A) pi/3 and 5pi/3 B) pi/6 and 11pi/6 C) pi/6 and 5pi/6 D) pi/3 and 2pi/3
 one year ago
 one year ago

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love_mathBest ResponseYou've already chosen the best response.1
secx=2. cosx=1/2, x=pi/3 and 5pi/3
 one year ago

GluttonousIntention09Best ResponseYou've already chosen the best response.0
@alexwee123 you add the secx in your step 3. So 4secx=8 secx=2
 one year ago

alexwee123Best ResponseYou've already chosen the best response.1
oh lol sorry about that :/
 one year ago

alexwee123Best ResponseYou've already chosen the best response.1
3(sec x1)= 5 sec x 3secx 3=5secx 4secx=8 secx=2 cosx=1/2 cos^1(cosx)=cos^1(1/2) x=pi/3+pi(n) where n=integers because range is within 0< x<2 pi. the answers are x=pi/3, 5pi/3
 one year ago

manu011Best ResponseYou've already chosen the best response.0
thank you for your help
 one year ago
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