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 2 years ago
find the solution set of the equation 3(sec x1)= 5 sec x in the interval of 0< x<2 pi.
A) pi/3 and 5pi/3
B) pi/6 and 11pi/6
C) pi/6 and 5pi/6
D) pi/3 and 2pi/3
 2 years ago
find the solution set of the equation 3(sec x1)= 5 sec x in the interval of 0< x<2 pi. A) pi/3 and 5pi/3 B) pi/6 and 11pi/6 C) pi/6 and 5pi/6 D) pi/3 and 2pi/3

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love_math
 2 years ago
Best ResponseYou've already chosen the best response.1secx=2. cosx=1/2, x=pi/3 and 5pi/3

GluttonousIntention09
 2 years ago
Best ResponseYou've already chosen the best response.0@alexwee123 you add the secx in your step 3. So 4secx=8 secx=2

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.1oh lol sorry about that :/

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.13(sec x1)= 5 sec x 3secx 3=5secx 4secx=8 secx=2 cosx=1/2 cos^1(cosx)=cos^1(1/2) x=pi/3+pi(n) where n=integers because range is within 0< x<2 pi. the answers are x=pi/3, 5pi/3

manu011
 2 years ago
Best ResponseYou've already chosen the best response.0thank you for your help
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