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jessejayne

  • 3 years ago

If I want to write a program that checks if a % list of numbers == 0 how would I write the list of numbers? Would I use a tuple, string, or ?

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  1. RoamingBlue
    • 3 years ago
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    Typically, you wouldn't use a string to hold a bunch of numbers. First, you need to decide if the list of numbers is mutable or not (mutable = changeable). If it IS mutable (you need to be able to add, remove or change values) use a list. If it isn't mutable ... use a tuple. pseudocode for this (please note that I didn't actually test this as valid code, just trying to give an overview of the concept) numberTuple = (1, 2, 3, 4, 5, 6) for (individualNumber) in numberTuple: if individulaNumber == 0: print "this number equals zero"

  2. pedja
    • 3 years ago
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    If I understand you well, you want to check if some number a is divisible by numbers in the list? It will be: for numer in number_list: if a % number == 0: print a, 'is divisible by', number Or, to check if a is divisible by every number in the list: def is_divisible(a, number_list): # function returns True if number a is divisible by every number in the list # else returns false for number in number_list: if a % number != 0: return False return True

  3. RoamingBlue
    • 3 years ago
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    Ah yes, pedja is correct ... I totally missed that a was a variable and just read it as the English word "a" and figured the % was a typo, silly me. You'd want to store the numbers in a list or tuple, then do exactly what pedja said and run a for loop over the list, checking each of the values in the list in turn

  4. jessejayne
    • 3 years ago
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    hmmmm... well I think I don't understand the syntax. Here is my program: http://dpaste.com/hold/785854/ I know that there is a better way to do this with way more fancy math and the program that I am trying to write will be slow, ect. However at this point I find it is better for me to learn the syntax using my own thoughts and ideas, rather than math that is complex. Once I can actually write something that doesn't take me hours to do then I will come back and complete the psets with different and more complex ideas. "steps off soap box* :P When I run this program it is not dividing the guess by every number in the number_list and print a result "composite number: " , guess. Rather it is taking the guess and dividing it by an integer in what seams to be a range (1, ?,1).

  5. RoamingBlue
    • 3 years ago
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    Consider how you're defining a composite number ... At line 8: if guess % number == 0: print 'composite number: ', guess Which translates to -- If the remainder of guess divided by number equals zero, this is a composite number. Which simply isn't true ... case in point (3). The remainder of three divided by three is zero so it passes the if clause on line 8 and is declared a composite number erroneously (it's prime not composite). Consider also the number 6 ... the remainder of six divided by six is also zero, yet this is a composite number. Consider testing instead to determine if it's a prime number.

  6. RoamingBlue
    • 3 years ago
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    Jesse - this is my take on how I'd handle the problem. http://dpaste.com/hold/785912/ Sorry if it got a bit mathy. I tried to comment the livin heck out of it to explain why I made the decisions I did.

  7. jessejayne
    • 3 years ago
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    I like the way that you did it. I understand it perfectly. I am still trying to make my program work unfortunately. This is where I am at this time: http://dpaste.com/hold/785944/ I did a prt scr of what I am getting to show you the problem, I just don't know how to fix it. It is the same as before. When I run this program it is not dividing the guess by every number in the number_list and print a result "composite number: " , guess. Rather it is taking the guess and dividing it by an integer in what seams to be a range (1, ?,1).

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  8. RoamingBlue
    • 3 years ago
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    Line nine ... if guess == number If that line is true then you know for a fact that it's a prime because it's in your explicit list of prime numbers and you're done checking that number You don't need the if/else after that. You just need to pick out the primes based on whether they're in your list, print them when you find them, consider everything else composite I think this might be what you're going for -- http://dpaste.com/hold/785952/

  9. jessejayne
    • 3 years ago
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    Oh my, I look like a major dum dum. lol I think I honestly stared at it so long my thoughts were turning to mush. And now that I am able to see the last post it shows how silly the original thought was. I still wonder why it was running through every integer rather than the list, but I'm just going to let that go for now. Again, you rock! Much love!

  10. RoamingBlue
    • 3 years ago
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    *grins* not dumb at all. We all have moments of staring at something so long our eyes cross and we just stop seeing it. Were I to make a guess, I'd venture that it was running through every integer because you used "pass" on line 12 instead of "break" which would break you out once you found a prime. So it would find the actual prime in the first if, then for non-primes drop into the else (which potentially reports false primes 'cause the prime check down in the else can't possibly find a prime 'cause they were all found in the initial if)

  11. bwCA
    • 3 years ago
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    http://dpaste.com/786135/

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