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EmilyJernigan
What is the inverse of the given relation? y = 3x + 9
\[x = {{y-9} \over 3} = {1 \over3}y - 3\]
to find the inverse you would switch the x and y and then solve for y so.. y = 3x + 9 x=3y+9 3y=x-9 y=1/3*x-3
Okay,, i had it right! Thank you