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Find \(x\).\[\left(2\cdot 7\right)^n+\left(3\cdot 5\right)^n5 \equiv 0 \pmod{x},\quad n\in\mathbb{Z}\]
 one year ago
 one year ago
Find \(x\).\[\left(2\cdot 7\right)^n+\left(3\cdot 5\right)^n5 \equiv 0 \pmod{x},\quad n\in\mathbb{Z}\]
 one year ago
 one year ago

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pawankumarBest ResponseYou've already chosen the best response.0
@ishaan ayye konsa grade ka problem ha?
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.0
hmm depends. what grade are you in?
 one year ago

pawankumarBest ResponseYou've already chosen the best response.0
but i don't have any i idea how to solve this problem....can we solve with mathmetical induction
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.0
hmm idk, i don't know how you could possibly solve it with mathematical induction.
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
is the power in LHS 'n' ? because then LHS modx will give u LHS for any and every value of x(and quotient=0)...as LHS does not depend on x....
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.0
yes, the exponential power is \(n\) and \(n\in \mathbb{Z}\).
 one year ago

experimentXBest ResponseYou've already chosen the best response.0
what is x? integer or real number?
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
i think its\[2\times7^n+3\times 5^n5 \]
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.0
hmm maybe. i can't be sure of the question, i got it yesterday on my test. does it solves the problem? @mukushla
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
yeah it solves the problem and answer will be \(x24\)...
 one year ago

Ishaan94Best ResponseYou've already chosen the best response.0
thanks. i got the same as well. i must have read the question wrong.
 one year ago
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