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anonymous
 3 years ago
Find \(x\).\[\left(2\cdot 7\right)^n+\left(3\cdot 5\right)^n5 \equiv 0 \pmod{x},\quad n\in\mathbb{Z}\]
anonymous
 3 years ago
Find \(x\).\[\left(2\cdot 7\right)^n+\left(3\cdot 5\right)^n5 \equiv 0 \pmod{x},\quad n\in\mathbb{Z}\]

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@ishaan ayye konsa grade ka problem ha?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmm depends. what grade are you in?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but i don't have any i idea how to solve this problem....can we solve with mathmetical induction

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmm idk, i don't know how you could possibly solve it with mathematical induction.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.0is the power in LHS 'n' ? because then LHS modx will give u LHS for any and every value of x(and quotient=0)...as LHS does not depend on x....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes, the exponential power is \(n\) and \(n\in \mathbb{Z}\).

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.0what is x? integer or real number?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think its\[2\times7^n+3\times 5^n5 \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmm maybe. i can't be sure of the question, i got it yesterday on my test. does it solves the problem? @mukushla

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah it solves the problem and answer will be \(x24\)...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks. i got the same as well. i must have read the question wrong.
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