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MathFrustration
Group Title
As a fundraiser, a school club is selling posters. The printer charges a $15 setup fee, plus $0.50 for each poster. Then the cost y in dollars to print x posters is given by the linear equation y=0.50x+15.
(a) What is the cost y in dollars to print 50 posters? Print 100 posters?
The printing of 50 posters costs $40.
I found this out by plugging 50 into the equation y=0.50(50)+15.
The printing of 100 posters costs $65.
I found this out doing the same thing by plugging in 100 to the equation y=0.50(100)+15.
(b) Find the number of posters x if the printer billed the club for costs of $110.00.
The number of posters, printed for $110.00, is: _________
(c) Write the information from parts (a) and (b) as three ordered pairs.
The first pair from (a) is:
The second pair from (a) is:
The pair from (b) is:
(d) Use the data from part (c) to graph the equation.
 one year ago
 one year ago
MathFrustration Group Title
As a fundraiser, a school club is selling posters. The printer charges a $15 setup fee, plus $0.50 for each poster. Then the cost y in dollars to print x posters is given by the linear equation y=0.50x+15. (a) What is the cost y in dollars to print 50 posters? Print 100 posters? The printing of 50 posters costs $40. I found this out by plugging 50 into the equation y=0.50(50)+15. The printing of 100 posters costs $65. I found this out doing the same thing by plugging in 100 to the equation y=0.50(100)+15. (b) Find the number of posters x if the printer billed the club for costs of $110.00. The number of posters, printed for $110.00, is: _________ (c) Write the information from parts (a) and (b) as three ordered pairs. The first pair from (a) is: The second pair from (a) is: The pair from (b) is: (d) Use the data from part (c) to graph the equation.
 one year ago
 one year ago

This Question is Closed

helpingtutors Group TitleBest ResponseYou've already chosen the best response.0
b) put y = 110 and solve for x which was 100 earlier!! c) write (x,y) pairs d) graph u can do using c
 one year ago
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