During a 4th of July weekend, 32 vehicles became trapped on the Sunshine Skyway Bridge while it was being repaved. A recent city ordinance decreed that only cars with 4 wheels and trucks with six wheels could be on the bridge at any given time. If there were 148 tires that needed to be replaced to due to damage, how many cars and trucks were involved in the incident?

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During a 4th of July weekend, 32 vehicles became trapped on the Sunshine Skyway Bridge while it was being repaved. A recent city ordinance decreed that only cars with 4 wheels and trucks with six wheels could be on the bridge at any given time. If there were 148 tires that needed to be replaced to due to damage, how many cars and trucks were involved in the incident?

Mathematics
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Basically you have two unknowns, so you need two equations in order to answer.
So let T be the number of trucks (with 6 wheels), and C be the number of cars (with 4 wheels)
C + T = 32

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Other answers:

(total number of vehicles is 32)
AND 6T + 4C = 148 (the total number of tires ruined is 148, 6 per truck and 4 per car)
now you can solve using those two equations: 1. 4(C + T) = 4*32 2. 4C + 4T = 128 3. Now pull back the second equation - 6T + 4C = 148, notice that since you have 4C in step (2), you can just subtract to get (T) alone. 4. 6T + 4C = 148 - 4T + 4C = 132 --------------- 2T = 16 T = 8
That would mean there are 32 - 8 cars, which is 24 cars.
ooops, sorry , 4*32 = 128, copied it over wrong in step (4)
4. 6T + 4C = 148 - 4T + 4C = 128 --------------- 2T = 20 T = 10
there we go, got kicked out, and there are 32 - 10 cars
then check your answer - so 10 + 22 = 32 vehicles total (yay), and then 10*6 + 22*4 = 148 (148 tires total). So it works!

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