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what is cot2a=0 Thus 2a=90˚....how did this happen?

Mathematics
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\[ cot2a = 0 => \frac{cos2a}{sin2a} = 0 => cos2a = 0 => 2a = cos(0)\]
wait i made a typo: \[ 2a = cos^{-1}(0)\]
since you know that \(cos^{-1}(0) = 90\)

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Other answers:

then \( 2a = 90\)
wait how did cot2a= cos2a/sin2a?
Firstly you should remember that: \[\cos(90) = 0\]
because \[ cota = \frac{cosa}{sina}\]
*cot
\[\large \cot(90^{\circ}) = 0\]
So you can replace 0 with cot(90): \[\cot(2a) = \cot(90)\]
im sorry but isnt cot= 1/tana?
well you can use that method if you remember whats cot(90)
Now as trigonometric ratio is same: So you can equate the angles: \[2a = 90\]
yes it because what tana?
what is*
yes it is but whats tan(a) then?*
oh cot also equals to x/y so cos/sin right??
Right..
ohhhh okay it makes sense
so i get that cos2a/sin2a = 0 but then what is next?
i typed the solution for you already..
Multiply by sin(2a) both the sides..
so it becomes cos2a (sin2a) = 0 (sin2a)
No.. There is one sin(2a) in the denominator too..
Can't you cancel sin(2a) with sin(2a) on left hand side ??
so does it become like this?
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Yep..
oh okay now i get the steps! thank you so much @waterineyes @Mimi_x3
Welcome dear..

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