sasogeek
if \(\large (2)^0=1 \) what is \(\large 2^0 \) ?



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apple_pi
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2^0 means 1 * 2^0 which as you know is 1 * (1) = 1

jiteshmeghwal9
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then it's will also 1

jiteshmeghwal9
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\((1)^0.(2)^0\)
1.1=1

apple_pi
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remember when doing x^y it means take x to the y and minus it, not take (x) to the y

jiteshmeghwal9
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\(2^0\)=1

apple_pi
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(2)^0 = 1

apple_pi
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not 2^0

shubhamsrg
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@jiteshmeghwal9
(2)^0 and 2^0 ,,both are diff..

jiteshmeghwal9
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\( \times\)\(2^0\)
=1

jiteshmeghwal9
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now it is right @apple_pi

apple_pi
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yes :D