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mukushla
 2 years ago
Best ResponseYou've already chosen the best response.2use this \[(b^2\frac{1}{b^2})^2+2=b^4+\frac{1}{b^4}=6\]\[(b^2\frac{1}{b^2})^2=4\]\[b^2\frac{1}{b^2}=(b+\frac{i}{b})^22i=\pm2\]

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.0omg!! buddy,,which planet are you from? seriously??
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