shubhamsrg
if
(b^4) + (1/b)^4 =6
then find the value of
(b+ i/b)^16
where i = sqrt(1)



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shubhamsrg
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@mukushla ??

mukushla
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use this
\[(b^2\frac{1}{b^2})^2+2=b^4+\frac{1}{b^4}=6\]\[(b^2\frac{1}{b^2})^2=4\]\[b^2\frac{1}{b^2}=(b+\frac{i}{b})^22i=\pm2\]

shubhamsrg
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omg!! buddy,,which planet are you from? seriously??

shubhamsrg
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thanks a lot!

mukushla
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lol....yw :)