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let u = sin(x)
2u^2 + u - 1 = 0

Can you solve this?

could you expand to the next step?

can't you just solve as a quadratic ... or cant you roll this way because its trig?

next step:
factorise:
(2u-1)(u+1)=0
thus
2u-1 = 0 or u+1=0
u=1/2 u=-1
now sub back sinx

is your domain for x specified?

sinx = 1/2 or sinx=-1 now solve for x

ahh, got it! I didn't realize it was a quadratic. Thank you so much!