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erynm

  • 3 years ago

2sin^2x+sinx-1=0

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  1. apple_pi
    • 3 years ago
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    let u = sin(x) 2u^2 + u - 1 = 0

  2. apple_pi
    • 3 years ago
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    Can you solve this?

  3. erynm
    • 3 years ago
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    could you expand to the next step?

  4. nabsz.j
    • 3 years ago
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    can't you just solve as a quadratic ... or cant you roll this way because its trig?

  5. Lizzardo
    • 3 years ago
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    next step: factorise: (2u-1)(u+1)=0 thus 2u-1 = 0 or u+1=0 u=1/2 u=-1 now sub back sinx

  6. apple_pi
    • 3 years ago
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    is your domain for x specified?

  7. Lizzardo
    • 3 years ago
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    sinx = 1/2 or sinx=-1 now solve for x

  8. erynm
    • 3 years ago
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    ahh, got it! I didn't realize it was a quadratic. Thank you so much!

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