anonymous
  • anonymous
2sin^2x+sinx-1=0
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
let u = sin(x) 2u^2 + u - 1 = 0
anonymous
  • anonymous
Can you solve this?
anonymous
  • anonymous
could you expand to the next step?

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anonymous
  • anonymous
can't you just solve as a quadratic ... or cant you roll this way because its trig?
anonymous
  • anonymous
next step: factorise: (2u-1)(u+1)=0 thus 2u-1 = 0 or u+1=0 u=1/2 u=-1 now sub back sinx
anonymous
  • anonymous
is your domain for x specified?
anonymous
  • anonymous
sinx = 1/2 or sinx=-1 now solve for x
anonymous
  • anonymous
ahh, got it! I didn't realize it was a quadratic. Thank you so much!

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