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pratu043
 2 years ago
How do you find the rationalising factor of root2 + root7  root10?
pratu043
 2 years ago
How do you find the rationalising factor of root2 + root7  root10?

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mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3multiply that by its conjugate @pratu043 what do you get?

pratu043
 2 years ago
Best ResponseYou've already chosen the best response.0By conjugate you mean: dw:1344952032255:dw

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3\[\large{(\sqrt{2}+\sqrt{7}\sqrt{10})(\sqrt{2}+\sqrt{7}+\sqrt{10})=?}\]

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3dw:1344952080072:dw

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3@pratu043 what do you get by multiplying that.. ?

pratu043
 2 years ago
Best ResponseYou've already chosen the best response.0How do you find the conjugate?

pratu043
 2 years ago
Best ResponseYou've already chosen the best response.0I only know how to find for binomial surds.

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3@pratu043 let the expression given be like this: \[\large{(\sqrt{2}+\sqrt{7})(\sqrt{10})}\]

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3I meant to say that: a+bc = (a+b)(c) right?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3dw:1344952309566:dw

pratu043
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1344952351465:dw What do you do with  root10?

pratu043
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1344952415376:dw sorry

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3ok leave that for once... what will be the conjugate of a+b ?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3right so let a = c+d and b = b now can u tell me what will be the new conjugate? : (c+d)+(b) conjugate = ?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3right so what will be the conjugate of : \[\large{(\sqrt{2}+\sqrt{7})(\sqrt{10})}\]

pratu043
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1344952630671:dw ok, I got the conjugate part.

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3right now : multiply this conjugate with original expression

pratu043
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1344952686106:dw right?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3good so we have: \[\large{2\sqrt{14}1}\] now:(√2 + √7  √10)[(√2 + √7 + √10) (2√14 + 1)] do this

pratu043
 2 years ago
Best ResponseYou've already chosen the best response.0But why should we do this?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3it is a step towards the answer

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3also try to check that out pratu that u did: can that be more simplified?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3@pratu043 you there?

pratu043
 2 years ago
Best ResponseYou've already chosen the best response.0do you mean that we should try and convert the irrationals in that expression to mixed surds?

pratu043
 2 years ago
Best ResponseYou've already chosen the best response.0I think I can handle it on my own now, thanks!!

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3(√2 + √7  √10)[(√2 + √7 + √10) (2√14 + 1)] \[\large{(\sqrt{2}+\sqrt{7}\sqrt{10})(\sqrt{2}+\sqrt{7}+\sqrt{10})(2\sqrt{14}+1)}\] \[\large{(9+2\sqrt{14}10)(2\sqrt{14}+1)=(2\sqrt{14}1)(2\sqrt{14}+1)=561=55}\]

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.3nice to hear best of luck
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